I:2x – y + z = 7
II:x + 2y – 5z = -1
III:x – y = 6
you can first use III and substitute x or y to eliminate it in I and II (in this case x):
III: x=6+y
-> substitute x in I and II:
I': 2*(6+y)-y+z=7
12+2y-y+z=7
y+z=-5
II':(6+y)+2y-5z=-1
3y+6-5z=-1
3y-5z=-7
then you can subtract II' from 3*I' to eliminate y:
3*I'=3y+3z=-15
3*I'-II':
3y+3z-(3y-5z)=-15-(-7)
8z=-8
z=-1
insert z in II' to calculate y:
3y-5z=-7
3y+5=-7
3y=-12
y=-4
insert y into III to calculate x:
x-(-4)=6
x+4=6
x=2
so the solution is
x=2
y=-4
z=-1
Answer:
x=11(12y-15)
Step-by-step explanation:
4x(3y-2)=7x+11
12xy-8x=7x+11
12xy-8x-7x=11
12xy-15x=11
x(12y-15)=11
x(12y-15)/(12y-15)=11/(12y-15)
x=11/(12y-15)
Answer:
-2 ≤ f(x) ≤ 4
Step-by-step explanation:
The range is the set or group of all the y-coordinates of the function. This means it has all the values from the bottom point at -2 to the top point at 4. It is written as an inequality.
-2 ≤ f(x) ≤ 4
Answer:
top left:1/5, 2/7, 3/5, 5/7, 31/35
top right:2/5, 2/3, 7/10, 4/5, 9/10
bottom left:9/8, 15/8, 13/6, 9/4, 15/6
bottom right:13/10, 13/6, 11/5, 25/6, 21/5
Step-by-step explanation:
Answer:
144 boys and 384 girls
Step-by-step explanation:
8 girls to every 3 boys. You can make an equation to solve this: 8x + 3x = 528. 528 = 11x. Then divide 528 by 11 to get 48. x=48. 8(48) = 384 girls. 3(48) = 144 boys.
