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jolli1 [7]
3 years ago
6

Which constant number would you add to both sides of the equation in order to complete the square for the quadratic function 1 =

x2 - 6x?​

Mathematics
2 answers:
UkoKoshka [18]3 years ago
8 0

Answer:

  • 9

Step-by-step explanation:

<u>Identity of the square of a sum:</u>

  • (a + b)² = a² + 2ab + b²

<u>Applied to given equation:</u>

  • 1 = x² - 6x
  • 1 = x² - 2*x*3
  • 1 + 3² = x² - 2*x*3 + 3²
  • 1 + 9 = (x - 3)²

The added constant is 9

Olin [163]3 years ago
8 0

Answer:

Solution given:

equation is:

1=x²-6x

x²-6x-1=0

comparing above equation with ax²+bx+c=0

we get

a=1

b=-6

c=-1

now

constant no.{(\frac{b}{2})}^{2}= {(\frac{-6}{2})}^{2}=\frac{36}{4}=9

<u>c</u><u>o</u><u>n</u><u>s</u><u>t</u><u>a</u><u>n</u><u>t</u><u> </u><u>r</u><u>e</u><u>q</u><u>u</u><u>i</u><u>r</u><u>e</u><u>d</u><u> </u><u>n</u><u>o</u><u> </u><u>i</u><u>s</u><u> </u><u>9</u><u>.</u>

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