Answer:
1. 21
2. 896
3. 20.9
Step-by-step explanation:
Use BODMAS/BIDMAS to solve.
Ok, so you are given the value of P=q+2
The substitution method tells us that we must insert the value we know, into the second equation, 4P+3q= -27
Doing so will give us 4(q+2)+3q= -27
For right now, lets just focus on the first part, 4(q+2)
We can simplify this by distributing(multiplying) the 4 to whats inside the variables.
This will give us 4q+8
now lets add this back to the rest of the equation >>> 4q+8+3q = -27
We can further simplify by adding like terms >>> 7q+8 = -27
subtract the 8 from both sides >>> 7q = -35
now divide both sides by 7 >>> q = -35/7
Therefor q = -5
EDIT*
now that we know q = -5 we can put q into the equation for P !
we know that p=q+2
so lets put q in now >>> p=(-5)+2
and simplify>>> p = -3
I hope this helps:)
Answer:
True
Step-by-step explanation:
Here, we want to check if the given equation does not intersect the x-axis
if it does not, then it has no real root
If the discriminant is less than zero, then it has no real roots and does not intersect the x-axis
The formula for the discriminant is;
D = b^2-4ac
In the question;
a = -1 , b = 6 , c = 10
so;
D = 6^2-4(-1)(10)
D = 36-40
D = -4
Since discriminant is less than zero, then there is no real root and the graph does not cross the x-axis
