You could make the numbers have a common denominator.
-3/7 --> -9/21
-2/3 --> -14/21
|-14/21| - |-9/21| = 5/21 difference.
5/21 is the distance.
<u>Given</u>:
The box plots show daily low temperatures for a sample of days in two different towns.
We need to determine the most appropriate comparison of the spreads.
<u>Interquartile range of town A:</u>
The interquartile range can be determined by subtracting the end values of the boxes.
Thus, we have;
Interquartile range = 40 - 20
Interquartile range = 20
Thus, the interquartile range for town A is 20.
<u>Interquartile range for town B:</u>
The interquartile range for town B is given by
Interquartile range = 45 - 35
Interquartile range = 10
Thus, the interquartile range for town B is 10.
Hence, the interquartile range (IQR) for town A, 20° is greater than the IQR for town B, 10°
Hence, Option A is the correct answer.
The <u><em>correct answer</em></u> is:
The equation is 7(c-0.75) = 2.80, and the regular price of a cookie is c = $1.15.
Explanation:
c is the regular price of a cookie. We know that today they are $0.75 less than the normal price; this is given by the expression c-0.75.
We also know if we buy 7 of them, the total is $2.80. This means we multiply our expression, c-0.75, by 7 and set it equal to $2.80:
7(c-0.75) = 2.80
To solve, first use the distributive property:
7*c-7*0.75 = 2.80
7c-5.25 = 2.80
Add 5.25 to each side:
7c-5.25+5.25 = 2.80+5.25
7c = 8.05
Divide each side by 7:
7c/7 = 8.05/7
c = $1.15.
