Answer:
(a) 4
(b) 4 * (7+3)
Step-by-step explanation:
(a) Let's first start by prime factorizing (finding the prime factors) 28 and 12:
12: 2*2*3
28: 2*2*7
We can see here they both share a common factor of 2*2, which is 4, therefore the GCF is 4.
(b) Factor a 4 out from the equation:

This gives us:
4 * (7+3)
Answer:
3/4 or 6/8
Step-by-step explanation:
6/8 when simplified is 3/4. That is the probability over the total.
Answer:
c. 6.2 ± 2.626(0.21)
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 101 - 1 = 100
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 100 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.626
The confidence interval is:

In which
is the sample mean while M is the margin of error.
The distribution of the number of puppies born per litter was skewed left with a mean of 6.2 puppies born per litter.
This means that 
The margin of error is:

In which s is the standard deviation of the sample and n is the size of the sample.
Thus, the confidence interval is:

And the correct answer is given by option c.
Using the distance formula,


Since ABCD has two pairs of opposite congruent sides, it is a parallelogram.
A. The equation to find the distance of the flowerbed from the hive is:
, where x is the distance.
B. The flowerbed is 2250 feet far from the hive.
<u><em>Explanation</em></u>
Suppose, the distance of the flowerbed from the hive is
feet.
The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.
As,
So, the time taken by the bee to reach the flowerbed
seconds and the time taken to fly back to the hive
seconds.
The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.
So, the equation will be.......

Thus, the distance of the flowerbed from the hive is 2250 feet.