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skelet666 [1.2K]
3 years ago
11

In which quadrant does θ lie given that sinθ<0 and cosθ<0?

Mathematics
2 answers:
ZanzabumX [31]3 years ago
6 0

Answer:

θ would lie in Quadrant III

Step-by-step explanation:

Review the attached file

Korolek [52]3 years ago
3 0

The third quadrant.⠀⠀⠀⠀⠀⠀⠀⠀

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I don't see a list of options, but I know that the answer is y = -4x + 6.

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Answer:

Correct

Step-by-step explanation:

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Factor the following:
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Factor the quadratic 2 x^2 - 7 x - 15. The coefficient of x^2 is 2 and the constant term is -15. The product of 2 and -15 is -30. The factors of -30 which sum to -7 are 3 and -10. So 2 x^2 - 7 x - 15 = 2 x^2 - 10 x + 3 x - 15 = x (2 x + 3) - 5 (2 x + 3):
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Factor 2 x + 3 from x (2 x + 3) - 5 (2 x + 3):
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4 0
4 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

Step-by-step explanation:

Supplementary angles add up to 180°.

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Supplement of θ = 180°-θ

θ = (180°-θ) + 148°

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θ = 164°

Supplement of θ = 180°-164° = 16°

6 0
3 years ago
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