Answer:
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<h2>Given </h2>
Triangle with:
- Base of n² -3,
- Midsegment of 39.
<h2>To find</h2>
<h2>Solution</h2>
As per definition of midsegment, it is connecting the midpoints of two sides and its length is half the length of the opposite side of the triangle.
So we have:
Solve it for n:
- n² - 3 = 78
- n² = 81
- n = √81
- n = 9
Correct choice is D.
Answer:
see below
Step-by-step explanation:
Every vertex moves twice as far from the center of dilation as it is in the pre-image.
Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).
Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).
Answer:
cos 45 degree = A/H
cos 45 degree = 2 square root 2 / x
x = 2 square root 2 / cos 45 degree
x = 4
Sin 45 degree = O/H
Sin 45 degree = y/ 4
4 x Sin 45 degree = y
y = 2.83
or
we could use tan
tan 45 degree = O/A
tan 45 degree = y / 2 square root 2
2 square root 2 x tan 45 degree = y
y = 2.83
i hope this would elp a little bit.
Answer: v = -3 or 6
Step-by-step explanation: