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snow_lady [41]
3 years ago
13

PLEASE HELP ME THIS ANSWER DRIVING ME CRAZY!!!

Mathematics
2 answers:
DaniilM [7]3 years ago
7 0
It’s blurry really blurry yuu needs make it more clear to get to get a answer
shtirl [24]3 years ago
6 0
It’s mad blurry so if you want an answer you have to make it more clear
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There is a 10% discount on all reusable water bottles this week. The regular price of a reusable water bottle is $20. Raul wants
Brilliant_brown [7]

Answer:$18

Step-by-step explanation:

6 0
3 years ago
What is the value of v? Help, please
9966 [12]

Answer:

v = 87

Step-by-step explanation:

the angle v+39 lies on a straight line. so substract v+39 from 180 to get the interior angle for that side.

afterwards, knowing that the sum of interior angles of a triangle = 180, form an equation with all the angles and solve for v

3 0
3 years ago
Two angles are supplementary. One angle is 16° less than three times the other. Find the measures of the angles
Ivan

Answer:

Step-by-step explanation:

x and y are supplementary angles, so their sum is 180°.

x+y = 180°

x is 16° less than three times y

x = 3y - 16°

(3y-16°) + y = 180°

4y = 196°

y = 49°

x = 3y-16° = 131°

7 0
3 years ago
Please help asap also ignore my answer.
anygoal [31]

Your answer should be 1.7 I hope this helps! Good Luck!

3 0
3 years ago
The roots of 2x^{2} + 3x = 4 are α and β. Find the simplest quadratic equation which has roots <img src="https://tex.z-dn.net/?f
elena-s [515]
2x^2+3x=4\implies2x^2+3x-4=0\implies x=\dfrac{-3\pm\sqrt{41}}4

Let \alpha be the root with the positive square root and \beta the root with the negative square root. Then

\dfrac1\alpha=\dfrac4{-3+\sqrt{41}}\quad\text{and}\quad\dfrac1\beta=\dfrac4{-3-\sqrt{41}}

The simplest quadratic with these roots can be written as

\left(x-\dfrac1\alpha\right)\left(x-\dfrac1\beta\right)=x^2-\left(\dfrac1\alpha+\dfrac1\beta\right)x+\dfrac1{\alpha\beta}=x^2-\dfrac34x-\dfrac12
4 0
3 years ago
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