Which equation best represents the linear function formed by the table?

The volume of a packing box is 5 – x cubic feet. The width of the box is x feet and the length is x – 2 feet. The height is give

photoshop1234 [79]

By definition we have that the volume is given by
V = h * w * l
where
V: Volume
h: height
w: width
l: length
Clearing the height we have:
h = V / (w * l)
h = (5 - x) / ((x) * (x - 2))
The expression is not defined for the values of x that make the denominator zero:
((x) * (x - 2)) = 0
x = 0
x = 2
Answer
h = (5 - x) / ((x) * (x - 2))
x = 0
x = 2

4 0

3 years ago

A 500-gallon tank initially contains 220 gallons of pure distilled water. Brine containing 5 pounds of salt per gallon flows int

Wittaler [7]

Answer: The amount of salt in the tank after 8 minutes is 36.52 pounds.

Step-by-step explanation:

Salt in the tank is modelled by the Principle of Mass Conservation, which states:

(Salt mass rate per unit time to the tank) - (Salt mass per unit time from the tank) = (Salt accumulation rate of the tank)

Flow is measured as the product of salt concentration and flow. A well stirred mixture means that salt concentrations within tank and in the output mass flow are the same. Inflow salt concentration remains constant. Hence:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = \frac{d(V_{tank}(t) \cdot c(t))}{dt}$

By expanding the previous equation:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt} + \frac{dV_{tank}(t)}{dt} \cdot c(t)$

The tank capacity and capacity rate of change given in gallons and gallons per minute are, respectivelly:

$V_{tank} = 220\\\frac{dV_{tank}(t)}{dt} = 0$

Since there is no accumulation within the tank, expression is simplified to this:

$c_{0} \cdot f_{in} - c(t) \cdot f_{out} = V_{tank}(t) \cdot \frac{dc(t)}{dt}$

By rearranging the expression, it is noticed the presence of a First-Order Non-Homogeneous Linear Ordinary Differential Equation:

$V_{tank} \cdot \frac{dc(t)}{dt} + f_{out} \cdot c(t) = c_0 \cdot f_{in}$ , where $c(0) = 0 \frac{pounds}{gallon}$ .

$\frac{dc(t)}{dt} + \frac{f_{out}}{V_{tank}} \cdot c(t) = \frac{c_0}{V_{tank}} \cdot f_{in}$

The solution of this equation is:

$c(t) = \frac{c_{0}}{f_{out}} \cdot ({1-e^{-\frac{f_{out}}{V_{tank}}\cdot t }})$

The salt concentration after 8 minutes is:

$c(8) = 0.166 \frac{pounds}{gallon}$

The instantaneous amount of salt in the tank is:

$m_{salt} = (0.166 \frac{pounds}{gallon}) \cdot (220 gallons)\\m_{salt} = 36.52 pounds$

3 0

3 years ago

Let f(x) = 3x+2 and g(x)=6x-7 find f(x)-g(x)

makkiz [27]

-3x+9
Hope this helps.

3 0

3 years ago

Read 2 more answers

Determine the range for the table.

Sladkaya [172]

Answer:

And the range is all real numbers except 0. The definition of range is the set of all possible values that the function will give when we give in the domain as input.

Step-by-step explanation :D give brainly

6 0

2 years ago

Can anyone help me with this please? <br> Do not answer if you do not know.

anastassius [24]

Answer: a

Step-by-step explanation:

6 0

3 years ago