Which equation best represents the linear function formed by the table?
1 answer:
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Point.
<h3>Further explanation</h3>- This is one of the classic problems of Euclidean geometry.
- The angle is determined by three points, we call it A, B, C, with A ≠ C and B ≠ C.
- We express an angle with three points and a symbol ∠. The middle point represents constantly vertex. We can, besides, give angle names only with vertices. For example, based on the accompanying image, the angle can be symbolized as ∠BAC, or ∠CAB, or ∠A.
Types of Angles
- The acute angle represents an angle whose measure is greater than 0° and less than 90°.
- The right angle is an angle that measures 90° precisely.
- The obtuse angle represents an angle whose measures greater than 90° and less than 180°.
- The straight angle is a line that goes infinitely in both directions and measures 180°. Carefully differentiate from rays that only runs in one direction.
<u>Note:</u>
Undefined terms are the basic figure that is undefined in terms of other figures. The undefined terms (or primitive terms) in geometry are a point, line, and plane.
These key terms cannot be mathematically defined using other known words.
- A point represents a location and has no dimension (size). It is marked with a capital letter and a dot.
- A line represent an infinite number of points extending in opposite directions that have only one dimension. It has one dimension. It is a straight path and no thickness.
- A plane represents a planar surface that contains many points and lines. A plane extends infinitely in all four directions. It is two-dimensional. Three noncollinear points determine a plane, as there is exactly one plane that can go through these points.
- Undefined terms are implemented to define a ray brainly.com/question/1087090
- Definition of the line segment brainly.com/question/909890
- What are three collinear points on a line? brainly.com/question/5795008
Keywords: the definition of an angle, the undefined term, line, point, line, plane, ray, endpoint, acute, obtuse, right, straight, Euclidean geometry
<span>The graph is attached.
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>
Explanation:
We can use the x- and y-intercepts to graph. The x-intercept of the first equation is 8, and the y-intercept is 8. The x-intercept of the second equation is -2, and the y-intercept is 2.
<span>
x-intercepts are where the data crosses the x-axis. At every one of these points, the y-coordinate will be 0; therefore we can substitute 0 for y and solve to get the value of the x-intercept.
For the first equation, we would have
8x+8(0)=64
8x=64.
Divide both sides by 8:
8x/8 = 64/8
x=8.
For the second equation,
2x-2(0)=-4
2x=-4.
Divide both sides by 2:
2x/2 = -4/2
x=-2.
y-intercepts are where the data crosses the y-axis. At every one of these points, the x-coordinate will be 0; therefore we can substitute 0 for x and solve to get the value of the y-intercept.
For the first equation,
8(0)+8y=64
8y=64.
Divide both sides by 8:
8y/8 = 64/8
y=8.
For the second equation,
2(0)-2y=-4
-2y=-4.
Divide both sides by -2:
-2y/-2 = -4/-2
y=2.
Plot these points for both equations and connect them to draw the line.</span></span>