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solong [7]
2 years ago
10

2. Sammie has 3 feet of ribbon. She is making bows for her friends that each use of 1/3 of a foot

Mathematics
1 answer:
lilavasa [31]2 years ago
3 0

Answer:

Sammy can make 9 bows.

Step-by-step explanation:

3 feet of Ribbon

1/3 for each bow

1/3 + 1/3 +1/3  = 3/3 or 1 so she can make 3 bows out of one foot of ribbon

so if you repeat this than  you should get 9 bows out of three feet of ribbion.

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How do i determine the domain and the equation of the vertical asymptote of the equation f(x)=ln (x+2)-1?
svetlana [45]
If I am reading the equation correctly, I do not believe it has a solution. 
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3 years ago
Can I get help on this please
Alekssandra [29.7K]
Hello!

I've attached the diagram.

For this problem, since you have a right triangle, you can use the Pythagorean Theorem to fine the length of the ladder (the hypotenuse of the triangle).

Pythagorean Theorem (where c is the hypotenuse):
a² + b² = c²

The triangle's leg lengths are 8 and 6; substitute into the theorem:
8² + 6² = c²

Simplify:
64 + 36 = c²
100 = c²
10 = c

Answer:
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4 0
2 years ago
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Although cities encourage carpooling to reduce traffic congestion, most vehicles carry only one person. For example, 64% of vehi
ira [324]

Answer:

a) 0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

b) 0.996 is the probability that more than half of the vehicles  carry just one person.    

Step-by-step explanation:

We are given the following information:

A) Binomial distribution

We treat vehicle on road with one passenger as a success.

P(success) = 64% = 0.64

Then the number of vehicles follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 10

We have to evaluate:

P(x \geq 6) = P(x =6) +...+ P(x = 10) \\= \binom{10}{6}(0.64)^6(1-0.64)^4 +...+ \binom{10}{10}(0.64)^{10}(1-0.79)^0\\=0.7291

0.7291 is the probability that more than half out of 10 vehicles carry just 1 person.

B) By normal approximation

Sample size, n = 92

p = 0.64

\mu = np = 92(0.64) = 58.88

\sigma = \sqrt{np(1-p)} = \sqrt{92(0.64)(1-0.64)} = 4.60

We have to evaluate the probability that more than 47 cars carry just one person.

P(x \geq 47)

After continuity correction, we will evaluate

P( x \geq 46.5) = P( z > \displaystyle\frac{46.5 - 58.88}{4.60}) = P(z > -2.6913)

= 1 - P(z \leq -2.6913)

Calculation the value from standard normal z table, we have,  

P(x > 46.5) = 1 - 0.004 = 0.996 = 99.6\%

0.996 is the probability that more than half out of 92 vehicles carry just one person.

5 0
2 years ago
I’m so confused please help , this is 100 points
sesenic [268]

Answer:

m`1 = 43` 2,3

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Step-by-step explanation:

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Which property of multiplication is used in the multiplication below?
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