M<PLA = 1/2 m PYA
110 = 1/2 (12x - 20)
12x - 20 = 220
12x = 220 + 20 = 240
x = 240 / 12 = 20
She would atleast have 30 friends
Set up the following equations:


110 represents the lengths of the length and width of the triangle, as you'll divide total perimeter of the rectangle, 220, by 2 to find the individual lengths. 20 is the difference between the length and width.
We'll use elimination for this system of equations, as there are opposite coefficients for W in both equations. Combine the two equations:

Divide both sides by 2 to get L by itself:
The length of the rectangle is 65 feet.Plug this value into the second equation:

Add W to both sides:

Subtract 20 from both sides:
The width of the rectangle is 45 feet.
Put the value of x = 6 to the eqpression 5x² + x - 7:
5(6)² + 6 - 7 = 5(36) + 6 - 7 = 180 + 6 - 7 = 179
<h3>Answer: 179</h3>
Okay, so this is just a basic multiplication problem. first, we need to divide to figure out how much the trout population grows after 1 year. If it doubles in 4 years, then it will rise by a quarter each single year. So to put that in terms of fractions, then for every year, the equation would be 250x1/4. So then we do the equation, coming up with 62.5. This means that the population rises roughly 63 fish a year. So after 1 year, you will have roughly 313 fish. (312.5 to be exact). Then to get that by ten years, we can just multiply the number that we got for one year by ten. 62.5x10=625. So then we add the 250 original trout, and 250+625=875. So after 10 years, there will be 875 trout.