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2 years ago

PLS HELP ME! I’m tired.

Mathematics

1 answer:

Igoryamba2 years ago

4 0

Answer:

30.5*10=350$

Step-by-step explanation:

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.

hope it helps

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H(x)=4x-2 find h(-9)

ki77a [65]

Answer:

Step-by-step explanation:

H(x) = 4x-2

H(-9) = 4(9)-2

H(-9) = 36 -2

H(-9) = 34

7 0

2 years ago

How are the symbols for greater than (>) and greater than or equal to (≥) related?

netineya [11]

Answer:

The greater than symbol is >. So, 9>7 is read as '9 is greater than 7'. The less than symbol is <. Two other comparison symbols are ≥ (greater than or equal to) and ≤ (less than or equal to).

Step-by-step explanation:

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2 years ago

Read 2 more answers

26.891 to the nearest ten thousands place

Ahat [919]

the number isn't large enough to round to the nearest ten thousandths.

that would be the 4th digit to the right of the decimal point, so we would need the 4th and 5th numbers to the right in order to round the answer.

6 0

2 years ago

Write an equation for the circle with endpoints of a diameter (9, 4) and (-3, -2)

inysia [295]

If the diameter is at (9,4) and (-3,-2), then the center of the circle is the midpoint of that segment.

and since we know that the radius of a circle is half of the diameter, whatever long that diameter segment is, the radius is half that.

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points }
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{ x_2 + x_1}{2}\quad ,\quad \cfrac{ y_2 + y_1}{2} \right)
\\\\\\
\left( \cfrac{-3+9}{2}~~,~~\cfrac{-2+4}{2} \right)\implies \stackrel{center}{(3~,~1)}$

$\bf -------------------------------\\\\
~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
\begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
% (a,b)
&&(~ 9 &,& 4~) 
% (c,d)
&&(~ -3 &,& -2~)
\end{array}
\\\\\\
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
d=\sqrt{(-3-9)^2+(-2-4)^2}\implies d=\sqrt{(-12)^2+(-6)^2}
\\\\\\
d=\sqrt{180}\qquad \qquad \qquad radius=\cfrac{\sqrt{180}}{2}$

$\bf -------------------------------\\\\
\textit{equation of a circle}\\\\ 
(x- h)^2+(y- k)^2= r^2
\qquad 
center~~(\stackrel{3}{ h},\stackrel{1}{ k})\qquad \qquad 
radius=\stackrel{\frac{\sqrt{180}}{2}}{ r}
\\\\\\
(x-3)^2+(y-1)^2=\left( \frac{\sqrt{180}}{2} \right)^2\implies (x-3)^2+(y-1)^2=\cfrac{(\sqrt{180})^2}{2^2}
\\\\\\
(x-3)^2+(y-1)^2=\cfrac{180}{4}\implies (x-3)^2+(y-1)^2=45$

7 0

2 years ago

ANSWER FAST!! All of the following angle pairs are ALWAYS congruent when a transversal passes through 2 parallel lines EXCEPT:

Murrr4er [49]

Answer:

Adjacent angles

Step-by-step explanation:

7 0

2 years ago