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lukranit [14]
3 years ago
6

How else can the ratio 14:1 be written

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0
14/1 basically 14 over 1
BigorU [14]3 years ago
7 0
If you multiply the ratio 14:1 by 2, you can get another form of 14:1 which is 28:2.

You can also decide to multiply the ratio by other numbers, like 3 or 4, but remember to multiply both sides of the ratio by that number.
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"18 less than a number"
Dmitriy789 [7]

Answer:

18 is 1 and 8 put togother.

Step-by-step explanation:

3 0
2 years ago
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Let f(x)=x^3 and g(x)= √x, and h(x)=x/3. Find each of the following: f(g(h(6)))
rewona [7]

Answer:

go from inside out.

h(x)=x/3

(\sqrt{2})^{3}=> h(6) = 6/3 = 2

g(x) = \sqrt{x}

=> g(h(6)) = g(2) = \sqrt{2}

f(x) = x^{3}

=> f(g(h(6))) = f(\sqrt{2} ) = (\sqrt{2} )^{3}

6 0
3 years ago
HELP i dont get it<br> this is so harddddd
Lady bird [3.3K]
B. the line is going up so it’s going to be positive not negative. the b value is gonna be negative 1 instead of positive because it crosses the y axis closer to -1 than it does 1
4 0
3 years ago
Evaluate the surface integral. s y ds, s is the helicoid with vector equation r(u, v) = u cos(v), u sin(v), v , 0 ≤ u ≤ 6, 0 ≤ v
Juliette [100K]

Compute the surface element:

\mathrm dS=\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

\vec r(u,v)=(u\cos v,u\sin v,v)\implies\begin{cases}\vec r_u=(\cos v,\sin v,0)\\\vec r_v=(-u\sin v,u\cos v,1)\end{cases}

\|\vec r_u\times\vec r_v\|=\sqrt{\sin^2v+(-\cos v)^2+u^2}=\sqrt{1+u^2}

So the integral is

\displaystyle\iint_Sy\,\mathrm dS=\int_0^\pi\int_0^6u\sin v\sqrt{1+u^2}\,\mathrm du\,\mathrm dv

=\displaystyle\left(\int_0^\pi\sin v\,\mathrm dv\right)\left(\int_0^6u\sqrt{1+u^2}\,\mathrm du\right)

=\dfrac23(37^{3/2}-1)

4 0
3 years ago
How many solutions 4(x-5)=3x+7
ohaa [14]
4(x-5)=3x+7 \\ \\ 4x - 20 = 3x + 7 \\ \\ 4x = 3x + 7 + 20 \\ \\ 4x = 3x + 27 \\ \\ 4x - 3x = 27 \\ \\ x = 27 \\ \\

The final result is: x = 27
5 0
3 years ago
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