Answer:
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Step-by-step explanation:
Let
S = 2b/(b+a)^2 + 2a/(b^2-a^2) factor denominator
= 2b/(b+a)^2 + 2a/((b+a)(b-a)) factor denominators
= 1/(b+a) ( 2b/(b+a) + 2a/(b-a)) find common denominator
= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a)) expand
= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a)) simplify & factor
= 2/(b+a)(b^2+a^2)/((b+a)(b-a)) simplify & rearrange
= 2(b^2+a^2)/((b+a)^2(b-a))
Numerator = 2(b^2+a^2) or equivalently 2b^2+2a^2
Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3
Scale factor is given by:
(length of larger figure)/(length of smaller figure)=(width of larger figure)/(width of the smaller figure)=3.4
The length of the larger figure will be given by:
length=(scale factor)*(length of smaller figure)
=3.4*6=20.4 cm
width of the larger figure will be given by:
width=(scale factor)*(width of smaller figure)
=3.4*4.5
=15.3 cm
Therefore the dimension of the new parallelogram will be 20.4 cm by 15.3 cm
Answer:
.83 cents
Step-by-step explanation:
Is this even a question, it seems to be more of a statement..
Make the coefficient of y the same in both equations:
To do this, multiply equation one by 2, and equation two by 5 (this will make the coefficient 10 in both).
14x + 10y = 38
-35x - 10y = -80
Eliminate the y variable by adding the equations from each other
(14x + 10y = 38)
+ (-35x - 10y = -80)
= -21x + 0y = -42
We now have -21x = -42. The y variable has been eliminated.
Solve for x
-21x = -42
Divide both sides by -21 to get x on its own.
x = 2
Substitute x into the equation to find y.
7*2+5y=19
14+5y=19
Subtract 14 from both sides.
5y=19-14
5y=5
Divide by 5 on both sides to get y on its own.
y=5/5
y=1
The answer is (2,1)
