let L = length and let W = width.
Use the equations 2L + 2W = 2750 
and L = 5W + 15
Then do the steps as follows -
1. Plug the equation for what L equals into the first equation
2(5W+15) + 2W = 2750
2. Then distribute the 2
10W + 30 + 2W = 2750
3. Then add like terms
12W + 30 = 2750
4. Then subtract 30 from both sides
12W = 2720
5. Divide by 12 on both sides
W = 226.67
6. Then plug that into the second equation
L = 5(226.67) + 15
L = 1148.35 should be the answer
 
        
             
        
        
        
Answer: C=[ (10) x (19.60)÷ (8)]
 
Step-by-step explanation:
Given , The cost of 8 books = $ 19.60
Then, By UNITARY method , the cost of one book = ( Cost of 8 books ) ÷ ( 8)
i.e. The cost of one book = ($19.60) ÷ ( 8) ...(i)
Now , cost of 10 books = (10) x (Cost of one book)
From (i) , we get
Cost of 10 books =$[ (10) x (19.60)÷ (8)]
 Let C be the cost of 10 books ( in dollars) .
So , the equation would help determine the cost of 10 :
C=[ (10) x (19.60)÷ (8)]
 
        
             
        
        
        
For the problem, we are asked t o calculate the volume of the cylindrical vase and it will represent the amount of water that Mary should pour. For a cylinder, the volume is calculated as follows:
V = πr²l
V = π(3)²(8)
<span>V = 226.19 in³ water needed</span>
        
             
        
        
        
Answer:
On occasions you will come across two or more unknown quantities, and two or more equations
relating them. These are called simultaneous equations and when asked to solve them you
must find values of the unknowns which satisfy all the given equations at the same time. 
Step-by-step explanation:
1. The solution of a pair of simultaneous equations
The solution of the pair of simultaneous equations
3x + 2y = 36, and 5x + 4y = 64
is x = 8 and y = 6. This is easily verified by substituting these values into the left-hand sides
to obtain the values on the right. So x = 8, y = 6 satisfy the simultaneous equations.
2. Solving a pair of simultaneous equations
There are many ways of solving simultaneous equations. Perhaps the simplest way is elimination. This is a process which involves removing or eliminating one of the unknowns to leave a
single equation which involves the other unknown. The method is best illustrated by example.
Example
Solve the simultaneous equations 3x + 2y = 36 (1)
5x + 4y = 64 (2) .
Solution
Notice that if we multiply both sides of the first equation by 2 we obtain an equivalent equation
6x + 4y = 72 (3)
Now, if equation (2) is subtracted from equation (3) the terms involving y will be eliminated:
6x + 4y = 72 − (3)
5x + 4y = 64 (2)
x + 0y = 8
 
        
             
        
        
        
So firstly, I'm going to be converting the mixed number into an improper fraction. To do this, multiply the whole number by the denominator and then add that product with the numerator and that will be your new numerator. In this case:
3 × 8 = 24, 24 + 3 = 27. 
Now since they have the same denominator, you can subtract the numerators.

Now simplify the number as such:

<u>In short, your answer is -17/4, or -4 1/4.</u>