Answer:
The ball is in the air for approximately 3.27 seconds ⇒ answer A
Step-by-step explanation:
* Lets explain how to solve the problem
- The height of the ball is modeled by the function
h(t) = -4.9 t² + 16 t
- We need to find the time that the ball is in the air
- The ball is in the air from its initial position and then return to the
same position
- That means h(t) = 0 because h(t) represent the height of the ball
from its initial position
∵ h(t) = -4.9 t² + 16 t
∵ h(t) = 0
∴ 0 = -4.9 t² + 16 t
- Add 4.9 t² to both sides
∴ 4.9 t² = 16 t
- Subtract 16 t from both sides
∴ 4.9 t² - 16 t = 0
- Take t as a common factor
∴ t (4.9 t - 16) = 0
- Equate each factor by 0
∴ t = 0 and 4.9 t - 16 = 0
∵ 4.9 t - 16 = 0 ⇒ add 16 for both sides
∴ 4.9 t = 16
- Divide both sides by 4.9
∴ t = 3.2653
∴ t = 0 ⇒ initial position
∴ t = 3.2653 seconds ⇒ final position
* <em>The ball is in the air for approximately 3.27 seconds</em>
Problem 1
We replace every copy of x with 4c and simplify like so:
f(x) = 8 - 5x
f(4c) = 8 - 5*4c
f(4c) = 8 - 20c is the answer
This is equivalent to -20c+8.
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Problem 2
Same idea as before, but this time we'll plug in x = 2-k
Each x gets replaced with (2-k)
f(x) = 8 - 5x
f(2-k) = 8 - 5(2-k)
f(2-k) = 8 - 10 + 5k
f(2-k) = -2 + 5k
This is the same as saying 5k - 2.
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Problem 3
The steps are similar to earlier.
f(x) = 8 - 5x
f(4p+3) = 8 - 5(4p+3)
f(4p+3) = 8 - 20p - 15
f(4p+3) = -7-20p
This is the same as writing -20p - 7.
Answer:
The distance between these two is 8.
Step-by-step explanation:
To find this, simply subtract the smaller from the larger.
11 - 3 = 8
Answer: 27a
Step-by-step explanation:
1. Simplify 4a×6 to 24a.
24a+3a
2. Simplify.
27a
You have to separate the rectangle and the triangle, then find the area of each and add them up.
area of the triangle,
(12×5)÷2=60÷2=30m squared.
area of the rectangle,
12×2=24m squared.
now add them up,
30+24=54m squared.
answer=54m squared
hope this helps......
