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Andreyy89
3 years ago
10

Find the number n of hours you need to study on Saturday so that mean number of hours you study per day is 1.5

Mathematics
1 answer:
Tema [17]3 years ago
4 0

Answer:

1 hour

Step-by-step explanation:

We are given that

Day       Hours

Sunday    0

Monday   1.5

Tuesday    2.5

Wednesday  2.5

Thursday       3

Friday            0

Saturday       n

Mean number of hours of  study per day=1.5

Mean=\frac{sum\;of\;data\;}{total\;number\;of\;data\;points}

Total number of days=7

Using the formula

1.5=\frac{0+1.5+2.5+2.5+3+0+n}{7}

1.5\times 7=9.5+n

10.5-9.5=n

n=1

Hence,  number of hours you need to study on Saturday=n=1

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PLZ HELP ME WITH GEOMETRY
Aloiza [94]

B a counterclockwise rotation about the origin of 90°

under a counterclockwise rotation about the origin

a point ( x , y ) → (- y, x)

figure Q to figure Q'

( 4,2 ) → (- 2, 4 )

(7, 5 ) → (- 5, 7 )

(3, 7 ) → (- 7 , 3 )

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the coordinates of the original points of the vertices of Q map to the corresponding points on the image Q'



7 0
4 years ago
A homeowner has an octagonal gazebo inside a circular area. Each vertex of the gazebo lies on the circumference of the circular
Tcecarenko [31]

If we draw the diagonals of the octagonal gazebo, the 4 diagonals divide the octagon into 8 triangles.

Note that each triangle is an isosceles triangle whose equal sides are x, the radius of the circle.

The top angle of each triangle is obtained by dividing the full angle by 8.

So, each top angle = \frac{360}{8}

= 45°

Now, in fig., consider one of the triangles Δ OAB. Draw an altitude OC from O to the opposite side AB.

This altitude OC bisects the top angle 45°.

Therefore, ∠ AOC = 22.5°.

Now, in Δ AOC,

sin 22.5=\frac{AC}{OA}

=\frac{AC}{x}

So, AC = x sin 22.5°

Note that, AB = 2 AC.

Therefore, AB = 2x sin 22.5°.

Also, cos 22.5=\frac{OC}{OA}

=\frac{OC}{x}

So, OC = x cos 22.5°.

Area of Δ AOB = \frac{1}{2}(AB)(OC)

= \frac{1}{2} × (2x sin 22.5°) × (x cos 22.5°)

= \frac{1}{2} x^{2} (2 sin 22.5° cos 22.5°)

= \frac{1}{2} x^{2} sin 45°

= x^{2} / 2\sqrt{2}

Area of the octagonal gazebo = 8 × one triangular area

= 8 × (x^{2} / 2\sqrt{2})

=2\sqrt{2} x^{2}

=2.828x^{2}

Area required for mulch = circular area - area of the gazebo

=3.14x^{2} -2.828x^{2}

=0.312x^{2}

Now, cost per unit area = $1.50.

Hence, total cost g(m) = area × cost per unit area

Total cost g(m) = 0.312x^{2} × 1.5

=0.468x^{2}

Hence, total cost g(m) = 0.468x^{2}.

4 0
3 years ago
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