Question

Consider a rectangle, where two adjacent vertices of a rectangle are located at the coordinates (-3 , 1) and (5 , 1). Two sides of this rectangle have a length of 6 units. Possible coordinates for one of the two missing vertices is ? The length of the diagonal of the rectangle is ? units.

Answer 1

Answer:

co-ordinates are (-3,7) and (5,7)

or

(-3,-5) and (5,-5)

length of diagonal=10 units

Step-by-step explanation:

$length=\sqrt{(5+3)^2+(1-1)^2} =\sqrt{64} =8\\slope ~of~length=\frac{1-1}{5+3} =0\\\\length ~of~rectangle~is~parallel~to~x-axis\\ width~ is~ parallel ~to~y- axis~and~is~6~units~away~from~length.\\other co-ordinates ~of~rectangle are~(-3,1+6)~and ~(5,1+6)~or~(-3,7)~and~(5,7)\\and~other~co-ordinates~are~(-3,1-6)~and~(5,1-6)~or~(-3,-5)~and~(5,-5)$

length of diagonal

d=\sqrt{8^2+6^2} =\sqrt{64+36} =\sqrt{100} =10 ~units\\or\\d=\sqrt{(5+3)^2+(1-7)^2} =\sqrt{64+36} =\sqrt{100} =10~units.