Answer:The number of seconds after rocket is released
Step-by-step explanation:
Given
The height of a rocket after it is released is modeled by
![h\left ( t\right )=-16t^2+32t+10](https://tex.z-dn.net/?f=h%5Cleft%20%28%20t%5Cright%20%29%3D-16t%5E2%2B32t%2B10)
Here t represent the number of seconds after the rocket is released.
Initial velocity can also be determined by this equation by differentiating the
w.r.t time
![\frac{\mathrm{d}h(t)}{\mathrm{d} t}=-32t+32](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7Dh%28t%29%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D-32t%2B32)
at t=o
![\frac{\mathrm{d}h(t)}{\mathrm{d} t}=32](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cmathrm%7Bd%7Dh%28t%29%7D%7B%5Cmathrm%7Bd%7D%20t%7D%3D32%20)
thus initial velocity will be 32 units/s
here,
Q is the midpoint of PR.
O is the midpoint of PN.
So, the line joining the midpoints of two sides is half and parallel to the third side.
So, QO is parallel to NR.
Now,
in triangles OPQ and NPR,
i) angle OPQ = angle NPR (common angle)
ii) angle POQ = angle PNR (corresponding angles)
iii) angle OQP = angle NRP (corresponding angles)
so,
triangle OPQ is similar to triangle NPR.
(by AAA similarity)
Answer:
Step-by-step explanation:
A tree diagram? I don't think so. Probably it would take a year's supply of paper to record all the possibilities. The question really is do you allow duplications and is 0 allowed to be the first digit.
I would think that both are fine.
So the total number for this number would be 10^9. There probably some sort of algorithm to reduce the number and to check if it is a legitimate choice for this number.
Answer:
y = x²/4 + x/2 + 21/4 ⇒ -9 ≤ x ≤ 7
Step-by-step explanation:
∵ x = 2t - 1
∴ 2t = x + 1 ⇒ t = (x + 1)/2
∵ y = t² + 5
∴ y = [(x + 1)/2]² + 5 = (x² + 2x + 1)/4 + 5
y = x²/4 + x/2 + 1/4 + 5 = x²/4 + x/2 + 21/4
∵ -4 ≤ t ≤ 4
∴ -9 ≤ x ≤ 7
Ok there is 7 students in total… the ratio of boys to girls is 5 to 2, so 5 divided by 7 is 0.714%