Money Transfer.
HOPE THIS HELPS!
Answer:
public class Person {
//fields
private int id;
private String name;
private Payment pay;
//constructor
public Person(String name, int id,
int startSal, int startBon){
this.name = name;
this.id = id;
this.pay = new Payment(startSal, startBon);
}
//method get name
public String getName(){
return name;
}
//method get id
public int getId(){
return id;
}
//method get start salary
public int getStartSalary(){
return pay.startSalary;
}
//method get start bonus
public int getStartBonus(){
return pay.startBonus;
}
//inner payment class
private class Payment{
int startSalary;
int startBonus;
public Payment(int sal, int bon){
this.startSalary = sal;
this.startBonus = bon;
<h2>
Answer:</h2>
F = 13
<h2>
Explanation:</h2>
Given:
x = false
y = 5
z = 1
F = (4%2)+2*Y +6/2 +(z&&x)
We solve this arithmetic using the order of precedence:
<em>i. Solve the brackets first</em>
=> (4 % 2)
This means 4 modulus 2. This is the result of the remainder when 4 is divided by 2. Since there is no remainder when 4 is divided by 2, then
4 % 2 = 0
=> (z && x)
This means (1 && false). This is the result of using the AND operator. Remember that && means AND operator. This will return false (or 0) if one or both operands are false. It will return true (or 1) if both operands are true.
In this case since the right operand is a false, the result will be 0. i.e
(z && x) = (1 && false) = 0
<em>ii. Solve either the multiplication or division next whichever one comes first.</em>
=> 2 * y
This means the product of 2 and y ( = 5). This will give;
2 * y = 2 * 5 = 10
=> 6 / 2
This means the quotient of 6 and 2. This will give;
6 / 2 = 3
<em>iii. Now solve the addition by first substituting the values calculated earlier back into F.</em>
F = (4%2)+2*Y +6/2 +(z&&x)
F = 0 + 10 + 3 + 0
F = 13
Therefore, the value of F is 13
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