Answer:
Step-by-step explanation:
In the associative property of multiplication, the product of the multiplication of 3 or more numbers is the same irrespective of how they are grouped. This means that irrespective of the bracket or which number comes first, the product will always be the same.
From the given scenarios, the pair of expressions that are equivalent using the Associative Property of Multiplication are
B 6(4a ⋅ 2) = (4a ⋅ 2) ⋅ 6
C 6(4a ⋅ 2) = 6 ⋅ 4a ⋅ 2
D6(4a ⋅ 2) = (6 ⋅ 4a) ⋅ 2
The results are the same irrespective of the arrangement of the numbers.
<span>3√20/√5
= </span>3 √4 √5<span> / √5
= 3 * 2
= 6
answer is </span><span>b)6</span>
Lets use 1 to solve this problem because it is easiest to show.
Multiply 1 by 1.3 for a 30% increase (1*1.3=1.3).
Then multiply 1.3 by .7 for a 30% decrease. (1.3*.7=.91)
Therefore the page had a 9% reduction from its original size or is 91% of its original size.
Answer:
The value is 
Step-by-step explanation:
From the question we are told that
The population proportion is 
The sample size is n = 563
Generally the population mean of the sampling distribution is mathematically represented as
Generally the standard deviation of the sampling distribution is mathematically evaluated as
=> 
=> 
Generally the probability that the proportion of persons with a college degree will differ from the population proportion by less than 5% is mathematically represented as
Here 
is the sample proportion of persons with a college degree.
So
![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P(\frac{[[0.05 -0.52]]- 0.52}{0.02106} < \frac{[\^p - p] - p}{\sigma } < \frac{[[0.05 -0.52]] + 0.52}{0.02106} )](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%28%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D-%200.52%7D%7B0.02106%7D%20%3C%20%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3C%20%5Cfrac%7B%5B%5B0.05%20-0.52%5D%5D%20%2B%200.52%7D%7B0.02106%7D%20%29)
Here
![\frac{[\^p - p] - p}{\sigma } = Z (The\ standardized \ value \ of\ (\^ p - p))](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5C%5Ep%20-%20p%5D%20-%20p%7D%7B%5Csigma%20%7D%20%20%3D%20Z%20%28The%5C%20standardized%20%5C%20%20value%20%5C%20%20of%5C%20%20%28%5C%5E%20p%20-%20p%29%29)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[\frac{-0.47 - 0.52}{0.02106 } < Z < \frac{-0.47 + 0.52}{0.02106 }]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%5Cfrac%7B-0.47%20-%200.52%7D%7B0.02106%20%7D%20%20%3C%20%20Z%20%20%3C%20%5Cfrac%7B-0.47%20%2B%200.52%7D%7B0.02106%20%7D%5D)
=> ![P( - (0.05 - 0.52 ) < \^ p < (0.05 + 0.52 )) = P[ -2.37 < Z < 2.37 ]](https://tex.z-dn.net/?f=P%28%20-%20%280.05%20-%200.52%20%29%20%3C%20%20%5C%5E%20p%20%3C%20%20%280.05%20%2B%200.52%20%29%29%20%3D%20P%5B%20-2.37%20%3C%20%20Z%20%20%3C%202.37%20%5D)
=> 
From the z-table the probability of (Z < 2.37 ) and (Z < -2.37 ) is
and
So
=>
=>
=>
Answer:
3rd option
Step-by-step explanation:
(
)(x)
= 
= 
← factorise numerator and denominator
= 
← cancel (2x + 1) on numerator/ denominator
= 
