1) Find the ending balance after these transactions: Transactions: A. Your

Mathematics

1 answer:

Makovka662 [10]2 years ago

5 0

The ending balance after these transactions is $ 59.25.

To find the ending balance after the transactions listed, the following calculation must be performed:

$ 822.67
+ $ 227.45
- $ 600.00
+ $ 50
- $ 100
- $ 200
- $ 3.50
- $ 2.50
- $ 134.87

822.67 + (227.45 + 50) - (600 + 100 + 200 + 3.50 + 2.50 + 134.87) = X
822.67 + 277.45 - 1040.87 = X
1,100.12 - 1,040.87 = X
59.25 = X

Therefore, the ending balance after these transactions is $ 59.25.

Learn more about maths in brainly.com/question/16376325

You might be interested in

Ln a+3 + ln a-3 = ln 16

Lilit [14]

$\bf log_{{ a}}(xy)\implies log_{{ a}}(x)+log_{{ a}}(y)\\\\
and\qquad \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-----------------------------\\\\
ln(a+3)+ln(a-3)=ln(16)\implies ln[(a+3)(a-3)]=ln(16)
\\\\\\
ln[a^2-3^2]=ln(16)\impliedby \textit{removing ln() from both sides}
\\\\\\
a^2-9=16\implies a^2=16+9\implies a^2=25
\\\\\\
a=\pm\sqrt{25}\implies a=\pm 5$

7 0

3 years ago

Solve for x. x3=125 Enter your answer in the box. x =

olchik [2.2K]

Answer:

x = 5

Step-by-step explanation:

=(-5-√-75)/2=(-5-5i√ 3 )/2= -2.5000-4.3301i

x =(-5+√-75)/2=(-5+5i√ 3 )/2= -2.5000+4.3301i

x = 5

source tiger-algebra.com

4 0

3 years ago

Read 2 more answers

Find the value of x so that the line passing through the points will have the given slope: (x,6) and (10,-3) with a slope of -3/

Lana71 [14]

$(x,6) \\
x_1=x \\
y_1=6 \\ \\
(10,-3) \\
x_2=10 \\ y_2=-3 \\ \\
\hbox{the slope: } m=\frac{y_2-y_1}{x_2-x_1}=\frac{-3-6}{10-x}=\frac{-9}{10-x} \\ \\
m=-\frac{3}{2} \\
\Downarrow \\
-\frac{3}{2}=\frac{-9}{10-x} \\
-\frac{3}{2}(10-x)=-9 \\
10-x=-9 \times (-\frac{2}{3}) \\
10-x=3 \times 2 \\
10-x=6 \\
-x=6-10 \\
-x=-4 \\
\boxed{x=4}$