1) Find the ending balance after these transactions: Transactions: A. Your

Mathematics

1 answer:

Makovka662 [10]2 years ago

5 0

The ending balance after these transactions is $ 59.25.

To find the ending balance after the transactions listed, the following calculation must be performed:

$ 822.67
+ $ 227.45
- $ 600.00
+ $ 50
- $ 100
- $ 200
- $ 3.50
- $ 2.50
- $ 134.87

822.67 + (227.45 + 50) - (600 + 100 + 200 + 3.50 + 2.50 + 134.87) = X
822.67 + 277.45 - 1040.87 = X
1,100.12 - 1,040.87 = X
59.25 = X

Therefore, the ending balance after these transactions is $ 59.25.

Learn more about maths in brainly.com/question/16376325

You might be interested in

If (x + 2 ) is a factor of x3 − 6x2 + kx + 10, k =

BartSMP [9]

If a binomial x-a is a factor of a polynomial p(x), then p(a)=0.

x+2 is a factor of p(x)=x³-6x²+kx+10, so p(-2)=0.

$p(-2)=0 \\
(-2)^3 - 6 \times (-2)^2 + k \times (-2) + 10=0 \\
-8-6 \times 4-2k+10=0 \\
-8-24-2k+10=0 \\
-2k-22=0 \\
-2k=22 \\
k=\frac{22}{-2} \\
\boxed{k=-11}$

8 0

3 years ago

Read 2 more answers

66768 in scientific notation

77julia77 [94]

6.6766*10^4 is that number in scientific notation

5 0

2 years ago

Find the equation of the line that passes through (1,3) and is perpendicular to y = 1 − 2 x

egoroff_w [7]

Answer:

$y=\displaystyle\frac{1}{2} x+\displaystyle \frac{5}{2}$

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept.

Perpendicular lines always have slopes that are negative reciprocals (ex. 1/2 and -2, 3/4 and -4/3)

Determine the slope (m):

$y = 1 -2x$

Rearrange into slope-intercept form:

$y = -2x+1$

Now, we can identify clearly that the slope is -2. Because perpendicular lines always have slopes that are negative reciprocals, a perpendicular line would have a slope of $\displaystyle\frac{1}{2}$ . Plug this into $y=mx+b$ :