Question

What are the solutions if 1/4x^2 =-1/2x+2?

Answer 1

Answer:

Step-by-step explanation:

$\frac{1}{4}x^{2}= \frac{1}{2}x +2\\\frac{1}{4}x^{2}- \frac{1}{2}x -2=0\\\frac{x^{2}-2x-8 }{4}=0\\\\x^{2}-2x-8=0\\ x^{2}-4x+2x-8=0\\x(x-4)+2(x-4) = 0\\(x-4) (x+2) = 0\\SO, \\x= 4 or x= -2$

Answer 2

Answer:

A. on edge 2020