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3 years ago

Please help at least do 3 questions please Don’t guess (can be more than one)

Mathematics

1 answer:

FromTheMoon [43]3 years ago

4 0

24 56 78 12 13 9 45 17 67 65 4 8

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at the end of a bike ride ,everyone drank a 16 fluid ounce bottle of sports drink.if 12 kids and 2 adults were on the bike ride

ZanzabumX [31]

224 i think because we are in the same class and i like boogers and poop

8 0

3 years ago

A rectangle has a height of 5 and a width of 4x^2 – 2x – 6.

bogdanovich [222]

The area of the rectangle is $20x^{2} -10x-30$ units.

Step-by-step explanation:

Step 1:

The area of a rectangle is obtained by multiplying the length with the width of the rectangle.

Considering this a whole rectangle, the length of the rectangle is 5 units and the width is the sum of $4x^{2}$ , $-2x$ , and -6.

So the length of the rectangle = 5 units and

the width of the rectangle $= 4x^{2} -2x-6$ units.

The area of a rectangle = (length)(width).

Step 2:

By substituting the known values, we get

The area of the rectangle $= (5) (4x^{2} -2x-6) = 20x^{2} -10x-30.$

So the area of the rectangle is $20x^{2} -10x-30$ units.

3 0

3 years ago

Can anyone figure this out?

Verizon [17]

$\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10})\qquad A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ NA=\sqrt{(6+3)^2+(3-10)^2}\implies NA=\sqrt{130} \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_2}{6}~,~\stackrel{y_2}{3})\qquad D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1}) \\\\\\ AD=\sqrt{(6-6)^2+(-1-3)^2}\implies AD=4 \\\\[-0.35em] ~\dotfill$

$\bf D(\stackrel{x_1}{6}~,~\stackrel{y_1}{-1})\qquad N(\stackrel{x_1}{-3}~,~\stackrel{y_1}{10}) \\\\\\ DN=\sqrt{(-3-6)^2+(10+1)^2}\implies DN=\sqrt{202}$

now that we know how long each one is, let's plug those in Heron's Area formula.

$\bf \qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{130}\\ b=4\\ c=\sqrt{202}\\[1em] s=\frac{\sqrt{130}+4+\sqrt{202}}{2}\\[1em] s\approx 14.81 \end{cases} \\\\\\ A=\sqrt{14.81(14.81-\sqrt{130})(14.81-4)(14.81-\sqrt{202})} \\\\\\ A=\sqrt{324}\implies A=18$

5 0

4 years ago

QUUESTION Today, everything at a store is on sale! The store offers a 20% discount.

julsineya [31]

Answer:

(x÷100)20

Step-by-step explanation:

x÷100 would be 1% so then to find 20% you would multiply by 20

6 0

3 years ago

Solve the equation 5

Brums [2.3K]

Should be A if I’m not mistaken

8 0

3 years ago