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3 years ago

Write 931 x 10-5 in standard notation.

Mathematics

2 answers:

Stella [2.4K]3 years ago

8 0

Answer:

0.000093

Step-by-step explanation:

Whitepunk [10]3 years ago

6 0

Answer:

0.000093

Step-by-step explanation:

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amanda exercised for 10 minutes every day in the first week, 20 minutes in the second week, 30 minutes in the third week, and 40

erastova [34]

Amanda in increasing her time exercising each week by a constants amount which means her method is linear so the answer is a

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3 years ago

Select all the correct statements.

myrzilka [38]

Answer: B C E F

Step-by-step explanation:

A is wrong as it should be the other way around

B is right

C is right

D is wrong as Natural numbers is a subset of rational numbers

E is correct

F is correct

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2 years ago

United Blood Services is a blood bank that serves more than 500 hospitals in 18 states. According to their website, a person wit

Anna11 [10]

Answer:

a) 0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b) 0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

Step-by-step explanation:

I am going to solve this question treating these events as Venn probabilities.

I am going to say that:

Event A: Person has type A blood.

Event B: Person has Rh- factor.

43% of people have type O blood

This means that $P(A) = 0.43$

15% of people have Rh- factor

This means that $P(B) = 0.15$

52% of people have type O or Rh- factor.

This means that $P(A \cup B) = 0.52$

a. Find the probability that a person has both type O blood and the Rh- factor.

This is

$P(A \cap B) = P(A) + P(B) - P(A \cup B)$

With what we have

$P(A \cap B) = 0.43 + 0.15 - 0.52 = 0.06$

0.06 = 6% probability that a person has both type O blood and the Rh- factor.

b. Find the probability that a person does NOT have both type O blood and the Rh- factor.

1 - 0.06 = 0.94

0.94 = 94% probability that a person does NOT have both type O blood and the Rh- factor.

6 0

3 years ago

Fifteen more than a number is written as...?

frozen [14]

Answer:

x + 15

Step-by-step explanation:

Since I don't know what this number is, I'm going to use the variable x to substitute for the value of the unknown number.

So it would just be x + 15 because addition is the operation of adding and the key words are usually more. Since one of the numbers is unknown, we can't get an answer like "100" because x is undefined.

Say x=100, then the number would be written as 115 in it's simplest form but you could also write it as 100+15. So I'm just using substitution.

3 0

3 years ago

Read 2 more answers

Samples of a cast aluminum part are classified on the basis of surface finish (in microinches) and edge finish. The results of 1

liubo4ka [24]

Answer:

a) P (A)= 88/102= 0.8627

(b) P (B)= 89/102= 0.8725

c) P (A`) = 14/102 = 0.1372

(d) P (A∩B) = 84/102 =0.8235

(e) P(AUB)= 93/102 = 0.9117

(f)P (A`UB) = 98/102= 0.96078

Step-by-step explanation:

edge

finish excellent good Total

<u>(A )surface finish excellent 84 4 88</u>

good ( B) ⇵ 5 9 14

Total 89 13 102

a) Upper P left-parenthesis Upper A right-parenthesis equals

P (A)= 88/102= 0.8627

All the elements of set A = 84+4= 88

(b) Upper P left-parenthesis Upper B right-parenthesis equals

P (B)= 89/102= 0.8725

All the elements of set B = 84+5= 89

c) Upper P left-parenthesis Upper A prime right-parenthesis equal

P (A`) = 14/102 = 0.1372

All the elements of Universal set U which are not elements of set A = 102- 88= 14

(d) Upper P left-parenthesis Upper A intersection Upper B right-parenthesis equals

P (A∩B) = 84/102 =0.8235

Only those elements of set A and set B which are common

(e) Upper P left-parenthesis Upper A union Upper B right-parenthesis equals

P(AUB)= 93/102 = 0.9117

Totalling elements of set A and B= 88+5= 93

(f) Upper P left-parenthesis Upper A prime union Upper B right-parenthesis equals

P (A`UB) = 98/102= 0.96078

All the elements of Universal set U which are not elements of set A and the elements of Set B = 5+9+ 84= 98

6 0

3 years ago