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3 years ago

10. Subtract thefractions.20 1 / 2 - 15 1/2 =*Bonus: Reduce thefraction.

Mathematics

1 answer:

BartSMP [9]3 years ago

3 0

Answer: 5

Step-by-step explanation:

$20\frac{1}{2}-15\frac{1}{2}$

$20-15(\frac{1}{2}-\frac{1}{2})$

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Consider a circle whose size can vary. The circumference of the circle is always 2 π 2π times as large as its radius. Let r r re

Alenkasestr [34]

Answer: $C=2\pi r$

Step-by-step explanation:

Let be "C" the circumference of the circle (in feet) and "r" the radius of the circle (in feet).

Based on the information provided in the problem, you know that the circumference of the circle is always $2\pi$ as large as its radius.

Notice that this indicates a multiplication. Then, this means that the circumference of the circle is always equal to $2\pi$ by "r".

Based on this, you can write the following formula that expresses the circumference "C" in terms of the radius "r":

$C=2\pi r$

4 0

3 years ago

Does 3,4, and 5 make a right triangle or not a right triangle?

S_A_V [24]

Answer:

I believe it does

Step-by-step explanation:

sorry if i am wrong

6 0

3 years ago

Read 2 more answers

PLEASE HELP ME I REALLY NEED HELP ON THIS QUESTION!!!!\

Vinil7 [7]

Answer:

$total \: earning \: in \: a \: week \: \\ = 14 \times \frac{77}{2} \\ = 7 \times 77 \\ = 539 \\ now \: pay \: for \: her \: friend \\ 539 \times \frac{1}{5} = 107.8$

5 0

3 years ago

The graph of which function has a minimum located at (4, –3)?

valentinak56 [21]

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^{2}+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^{2}+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^{2}+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ but is not a minimum

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^{2}-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^{2}-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^{2}-4x+4)$

$f(x)-1=(x^{2}-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^{2}$

$f(x)=(x-2)^{2}+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^{2}-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^{2}-16x$

Factor the leading coefficient

$f(x)-35=2(x^{2}-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^{2}-8x+16)$

$f(x)-3=2(x^{2}-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^{2}$

$f(x)=2(x-4)^{2}+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^{2}-16x+29$

7 0

3 years ago

Read 2 more answers

Peter's Party Zone sells cups in packages of 666 and plates in packages of 888.

lilavasa [31]

Answer:

the answer would be 24

Step-by-step explanation:

what you would need to do is find the LCM of 6 and 8

so the lcm of 6 and 8 =2 times 2 times 2 times 3= 24\

HOPE THIS HELPED<333

5 0

3 years ago

10. Subtract thefractions.20 1 / 2 - 15 1/2 =*Bonus: Reduce thefraction.​

10. Subtract thefractions.20 1 / 2 - 15 1/2 =*Bonus: Reduce thefraction.