Write a quadratic function that reflects the x axis, stretches by a factor of 5, and shifts left 6 and up 3
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The points of new triangle is (3,-2), (6,-3) and (2,-5).
<u>Step-by-step explanation:</u>
The given points in the triangle A(-3,7), B(9,3) and C(-7,-5).
The scale factor is and centered at point (5,-5).
The formula to dilate a point that is not centered on a origin is given by,
D(x,y)=(h+t(x-h),k+t(y-t)).
where (h,k) is the center point.
To find A',
D(-3,7)=(5-2, -5+3).
D(-3,7)=(3,-2).
To find B',
D(9,3) = (5+1,-5+2).
D(9.3)=(6,-3).
To find C',
D(-7,-5)=(5-3,-5+0).
D(-7,-5)=(2,-5).
∴ The points of new triangle is (3,-2), (6,-3) and (2,-5).
The scatter graph of the data is shown in the first picture below
The 'line of best fit' shows a negative gradient
Part A: The most likely coefficient is -0.98.
If the coefficient is -1, then each point would be exactly on the straight line (which they are not as shown on the graph). The graph however still shows a strong negative coefficient. It can be seen from the close distance of each point from the line of best fit. So -0.5 and -0.02 is unlikely as they show weak negative correlation
Part B: Refer to the second picture to see the horizontal and vertical distance between day 15 and day 20
The horizontal distance is 5 units
The vertical distance is read between 61 and 71.5, hence it's 10.5
The slope = Vertical distance ÷ Horizontal Distance = 10.5÷5 = 2.1
The 'downhill' slope shows a negative gradient, hence the value of the slope is -2.1
The value of the slope shows that the surface area of the lake shrinks by 2.1 for every one day
Part C: The data in the table represents the relation between two variables. Since one variable doesn't cause the change in the other variable, the data table represents correlation rather than a causation.
The 'line of best fit' shows a negative gradient
Part A: The most likely coefficient is -0.98.
If the coefficient is -1, then each point would be exactly on the straight line (which they are not as shown on the graph). The graph however still shows a strong negative coefficient. It can be seen from the close distance of each point from the line of best fit. So -0.5 and -0.02 is unlikely as they show weak negative correlation
Part B: Refer to the second picture to see the horizontal and vertical distance between day 15 and day 20
The horizontal distance is 5 units
The vertical distance is read between 61 and 71.5, hence it's 10.5
The slope = Vertical distance ÷ Horizontal Distance = 10.5÷5 = 2.1
The 'downhill' slope shows a negative gradient, hence the value of the slope is -2.1
The value of the slope shows that the surface area of the lake shrinks by 2.1 for every one day
Part C: The data in the table represents the relation between two variables. Since one variable doesn't cause the change in the other variable, the data table represents correlation rather than a causation.