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Paha777 [63]
3 years ago
15

Write a quadratic function that reflects the x axis, stretches by a factor of 5, and shifts left 6 and up 3

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Answer:

y=(x+6)^5+3

Step-by-step explanation:

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One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times sm
sergey [27]

One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel

<h3><u>Solution:</u></h3>

Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.  

We have to prove that the lines are parallel.

If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.

Now, the 1st angle will be 1/6 of right angle is given as:

\begin{array}{l}{\rightarrow 1^{\text {st }} \text { angle }=\frac{1}{6} \times 90} \\\\ {\rightarrow 1^{\text {st }} \text { angle }=15 \text { degrees }}\end{array}

And now, 15 degrees is 11 times smaller than the other  

Then other angle = 11 times of 15 degrees

\text {Other angle }=11 \times 15=165 \text { degrees }

Now, sum of angles = 15 + 165 = 180 degrees.

As we expected their sum is 180 degrees. So the lines are parallel.

Hence, the given lines are parallel

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4 years ago
Need help please <br> It will be good if I get the answer as soon as possible please and thanks
Ahat [919]

Answer:

B 71 & 71

Step-by-step explanation:

OP is an angle bisector

3 0
3 years ago
Read 2 more answers
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