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Maslowich
3 years ago
12

What is the greatest commen factor for 32 and 72

Mathematics
2 answers:
ladessa [460]3 years ago
8 0
8 is the greatest component.
Burka [1]3 years ago
4 0
32not
16not
8 yes 4*8=32 9*8=72
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4. A loan made on March 12 is due September 10 of the following year. Find the exact time for the loan in a non-leap year and a
saul85 [17]

Answer:

182 days

Step-by-step explanation:

Given:

Date on which loan is made = March 12

Due date of the loan = September 10

Now,

The months in between March and September and the number of days in the particular months are

Month                          Number of days

April                               30

May                                31

June                               30

July                                 31

August                            31

------------------------------------------

Total number of days =  153

also,

Number of days left in March after 12 are (31 - 12 ) = 19 days

and,

Number of days in September before the due date = 10 days

Hence, the total time for loan = 19 + 153 + 10 = 182 days

since the included months does not have the month of February. Therefore,

the time for both leap year and non-leap year will remain same.

7 0
3 years ago
PLEASE HELP!
Ierofanga [76]

Answer:

even number can be divided by two without areminder

3 0
3 years ago
To Sophia can spend at most $50 on clothes. If x is the amount of money Sophia can spend on clothes
Veronika [31]

Answer:

x ≤ 50

Step-by-step explanation:

7 0
3 years ago
If: AB= 2x + 6, AC = 51, and BC=6x +5, Find BC.
Marina86 [1]

Answer:

<h3>Assuming A, B, and C are collinear and B is between A and C then BC = 35 </h3>

Step-by-step explanation:

Assuming A, B, and C are collinear and B is beetween A and C

AB + BC  = AC

2x + 6 + 6x + 5 = 51

 8x + 11 = 51

    8x = 40

     x = 5

BC = 6x+5 = 6×5 + 5 = 35

3 0
3 years ago
Can someone please help me with these problems and show work, if the answer isn’t with work I will remove your comment and you w
MrRissso [65]

m∠B = 57.52°, m∠B = 70.8°, AB = 46.03 km and AC = 39.08 ft. This can be obtained using the Laws of cosine formula and Laws of sine formula.

<h3>Find the required angles and sides:</h3>
  • Laws of cosine formula,

In a triangle ABC,

⇒ a² = b² + c² - 2bc cos A

⇒ b² = a² + c² - 2ac cos B

⇒ c² = a² + b² - 2ab cos C

where a, b and c are sides of a triangle and A, B and C are the angles of a triangle.

  • Laws of sine formula,

In a triangle ABC,

⇒ \frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}

where a, b and c are sides of a triangle and A, B and C are the angles of a triangle.

 

In the question we can use the laws of cosine formula and laws of sine formula,

5) Given that,

AB = c = 13 km

AC = b = 21 km

m∠A = 91°

By using Laws of cosine formula,

⇒ a² = b² + c² - 2bc cos A

a² = 21² + 13² - 2(21)(13) cos 91°

a² = 441 + 169 - 546 (-0.0174524064)    

a² = 610 + 9.52901391 = 619.529014

⇒ a = 24.89 km

By using Laws of sine formula,

⇒ \frac{sinA}{a} =\frac{sinB}{b} =\frac{sinC}{c}

sin 91°/24.89 = sin B/21

sin B = 0.999847695×21/24.89 = 0.843583833

⇒ m∠B = 57.52°

 

6) Given that,

AB = c = 11 cm

BC = a = 13 cm

AC = b = 14 cm

By using Laws of cosine formula,

⇒ b² = a² + c² - 2ac cos B

14² = 13² + 11² - 2(13)(11) cos B

196 = 169 + 121 - 286 cos B

196 = 290 - 286 cos B

cos B = 94/286

cos B = 0.328671329

⇒ m∠B = 70.8°

 

7) Given that,

AC = b = 24 km

BC = a = 26 km

m∠C = 134°

By using Laws of cosine formula,

⇒ c² = a² + b² - 2ab cos C

c² = 26² + 24² - 2(26)(24) cos 134°

c² = 676 + 576 - 1248 (-0.69465837)

c² = 1252 + 866.933646 = 2118.93365

⇒ AB = c = 46.03 km

8) Given that,

AB = c = 26 ft

BC = a = 21 ft

m∠B = 112°

By using Laws of cosine formula,

⇒ b² = a² + c² - 2ac cos B

b² = 21² + 26² - 2(21)(26) cos 112°

b² = 441 + 676 - 1096 (-0.374606593)

b² = 1117 + 410.568826 = 1527.56883

⇒ AC = b = 39.08 ft

Hence m∠B = 57.52°, m∠B = 70.8°, AB = 46.03 km and AC = 39.08 ft.

Learn more about Laws of cosine and Laws of sine here:

brainly.com/question/17289163

#SPJ1

4 0
1 year ago
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