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AveGali [126]
2 years ago
11

Please answer me write a statement that why isnt 6.5 / 0.5 = 3.25

Mathematics
1 answer:
REY [17]2 years ago
4 0

Answer:

13

Step-by-step explanation:

It's not 3.25 because if you simplify 6.5 and 0.5, you get 65 and 5 which if you divide is 13.

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Plz help i will mark brainlist
iragen [17]
Y=x+4
3x+Y=-8

3x+x+4=-8
X=-3. Substitute the value of x


Y=-3+4
Y=1

(X,Y)= (-3,1)

So the answer is C
6 0
3 years ago
Read 2 more answers
 what would be the equation of a line that passes through (3,-4) with slope 2/3
Len [333]

Answer:

y = 2/3x - 6

Step-by-step explanation:

Use the slope intercept equation, y = mx + b

Plug in the slope and given point, then solve for b

y = mx + b

-4 = 2/3(3) + b

-4 = 2 + b

-6 = b

Plug in the slope and b into the equation

y = 2/3x - 6

So, the equation of the line is y = 2/3x - 6

7 0
2 years ago
An online file storage site offers a payment plan where users
lozanna [386]

Answer:   95.40

Step-by-step explanation:

7.95*12=95.40

6 0
2 years ago
Find a parametric representation for the part of the cylinder y2 + z2 = 49 that lies between the planes x = 0 and x = 1. x = u y
sweet-ann [11.9K]

Answer:

The equation for z for the parametric representation is  z = 7 \sin (v) and the interval for u is 0\le u\le 1.

Step-by-step explanation:

You have the full question but due lack of spacing it looks incomplete, thus the full question with spacing is:

Find a parametric representation for the part of the cylinder y^2+z^2 = 49, that lies between the places x = 0 and x = 1.

x=u\\ y= 7 \cos(v)\\z=? \\ 0\le v\le 2\pi \\ ?\le u\le ?

Thus the goal of the exercise is to complete the parameterization and find the equation for z and complete the interval for u

Interval for u

Since x goes from 0 to 1, and if x = u, we can write the interval as

0\le u\le 1

Equation for z.

Replacing the given equation for the parameterization y = 7 \cos(v) on the given equation for the cylinder give us

(7 \cos(v))^2 +z^2 = 49 \\ 49 \cos^2 (v)+z^2 = 49

Solving for z, by moving 49 \cos^2 (v) to the other side

z^2 = 49-49 \cos^2 (v)

Factoring

z^2 = 49(1- \cos^2 (v))

So then we can apply Pythagorean Theorem:

\sin^2(v)+\cos^2(v) =1

And solving for sine from the theorem.

\sin^2(v) = 1-\cos^2(v)

Thus replacing on the exercise we get

z^2 = 49\sin^2 (v)

So we can take the square root of both sides and we get

z = 7 \sin (v)

4 0
3 years ago
(40 pts)can you factor the difference of square?perfect square trinomials?
stira [4]

Answer:

Step-by-step explanation:

The difference of two squares may be represented by the formula:  a^2-b^2,

which can be factored as (a+b)(a-b)

A perfect square trinomial may be represented by the formula: a^(2)-2ab+b^2 or  a^(2)+2ab+b^2, depending on the sign of b

if b is negative: use the formula a^(2)-2ab+b^2, which can be factored as (a-b)*(a-b) or (a-b)^(2)

if b is positive: use the formula a^(2)+2ab+b^2, which can be factored as (a+b)*(a+b) or (a+b)^(2)

7 0
3 years ago
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