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2 years ago

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Lashonda's penny bank is

1 answer:

Vinil7 [7]2 years ago

5 0

Loshonda’s bank can hold 480 pennies because when it was half full it was 240 and then you multiply 240 by 2 and you get 480. I don’t know if this is right. i’m sorry if it isn’t :(

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Evaluate the function.

Natali5045456 [20]

As you may already be familiar, these functions f(x) and g(x) are piecewise. They consist of multiple functions with different domains.

1. For #1, the given input is f(0). Since 0≤1, you should use the first equation to solve. f(0)=3(0)-1 ➞ f(0)=-1
2. Continue to evaluate the given input for the domains given. 1≤1, therefore f(1)=3(1)-1➞f(1)=2
3. 5>1, therefore f(5)=1-2(5)➞f(5)=-9
4. -4≤1; f(-4)=3(-4)-1➞f(-4)=-13
5. -3<0<1; g(0)=2
6. -3≤-3; g(-3)=3(-3)-1➞g(-3)=-10
7. 1≥1; g(1)=-3(1)➞g(1)=-3
8. 3≥1; g(3)=-3(3)➞g(3)=-9
9. -5≤-3; g(-5)=3(-5)-1➞g(-5)=-16

Hope this helps! Good luck!

5 0

3 years ago

Read 2 more answers

Help please?? I’m being timed!!

weqwewe [10]

Answer:

answer is is option 3 all the best for examination

6 0

2 years ago

Read 2 more answers

2 points) Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One

Stells [14]

$y'=(t+y)^2-1$

Substitute $u=t+y$ , so that $u'=y'$ , and

$u'=u^2-1$

which is separable as

$\dfrac{u'}{u^2-1}=1$

Integrate both sides with respect to $t$ . For the integral on the left, first split into partial fractions:

$\dfrac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)=1$

$\displaystyle\int\frac{u'}2\left(\frac1{u-1}-\frac1{u+1}\right)\,\mathrm dt=\int\mathrm dt$

$\dfrac12(\ln|u-1|-\ln|u+1|)=t+C$

Solve for $u$ :

$\dfrac12\ln\left|\dfrac{u-1}{u+1}\right|=t+C$

$\ln\left|1-\dfrac2{u+1}\right|=2t+C$

$1-\dfrac2{u+1}=e^{2t+C}=Ce^{2t}$

$\dfrac2{u+1}=1-Ce^{2t}$

$\dfrac{u+1}2=\dfrac1{1-Ce^{2t}}$

$u=\dfrac2{1-Ce^{2t}}-1$

Replace $u$ and solve for $y$ :

$t+y=\dfrac2{1-Ce^{2t}}-1$

$y=\dfrac2{1-Ce^{2t}}-1-t$

Now use the given initial condition to solve for $C$ :

$y(3)=4\implies4=\dfrac2{1-Ce^6}-1-3\implies C=\dfrac3{4e^6}$

so that the particular solution is

$y=\dfrac2{1-\frac34e^{2t-6}}-1-t=\boxed{\dfrac8{4-3e^{2t-6}}-1-t}$

3 0

2 years ago

A standard bathtub holds 60 gallons of water. A full tub drains 12 gallons per minute. Which of the following tables best repres

masya89 [10]

J.

x represents the minutes and y shows how many gallons over that time.

5 0

2 years ago

A car traveled 88 km in 1 hour, 90 km in the next 2 hours, and then 76 km in 1 hour before reaching its destination. what was th

luda_lava [24]

The formula for Average speed = $\frac{Total Distance}{Total Time}$

The car travels 80 km in 1 hour.

Then the car travels 90 km in 2 hours.

And finally the car travels 76 km in 1 hour

So the total distance covered by the car = 80 + 90 + 76 = 246 km

The total time taken to cover this distance = 1 + 2 + 1 = 4 hours.

So average speed = $\frac{246}{4}= 61.5$

The average speed of the car is 61.5 km / h

3 0

3 years ago