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leonid [27]
3 years ago
10

4. Jake wants to make a garden with a border in the corner of his yard. He has lumber in several different lengths. Which three

lengths could NOT be used to make a right triangle to fit into the corner of his yard? O 5 ft., 12 ft., 13 ft. O 9 ft., 12 ft., 15 ft. O 16 ft., 12 ft., 20 ft. 0 0 O 10 ft., 12 ft., 15 ft.​
Mathematics
1 answer:
antoniya [11.8K]3 years ago
6 0

Answer:

<h3>10 ft., 12 ft., 15 ft.​</h3>

Step-by-step explanation:

Note that for a right triangle, the sum of the square of the hypotenuse is equal to the sum of square of the opposite and the adjacent.

Note that the hypotenuse is the longest side

Checking the given sides 10 ft., 12 ft., 15 ft.​

Hypotenuse = 15ft (longest side)

Take the square of 15

15² = 225

Take the sum of square of other two sides

12²+10²

= 144 + 100

= 244

Since 225≠244, hence the three length could not be used to make a right triangle to fit into the corner of his yard

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strojnjashka [21]

Answer:

x = 0

Step-by-step explanation:

{2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {9}^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {( {3}^{2}) }^{x } } \\  \\ {2}^{x} - {3}^{x} = \sqrt{ {6}^{x} } - \sqrt{ {({3)}^{2x}}}\\  \\ {2}^{x} -  \cancel{{3}^{x}} = \sqrt{ {6}^{x} } - \cancel{ {3}^{x} } \\  \\ {2}^{x} = \sqrt{ {6}^{x} } \\ squaring \: both \: sides \\  \\  {( {2}^{x} )}^{2}  =  {(\sqrt{ {6}^{x} })}^{2}  \\  \\  {2}^{2x}  =  {6}^{x}  \\  \\   {2}^{2x}  =  {(2 \times 3)}^{x}  \\  \\   {2}^{2x}  =  {2 ^{x}  \times 3}^{x}  \\  \\  \frac{ {2}^{2x}  }{ {2}^{x}  } =  3^{x}  \\  \\   {2}^{2x - x}  =  {3}^{x}  \\  \\  {2}^{x}  =  {3}^{x}  \\  \\   \frac{ {2}^{x} }{ {3}^{x} }  = 1 \\  \\  \bigg(  \frac{2}{3} \bigg)^{x}  = 1 \\  \\  \implies \: x = 0 \\  \\  \because \: for \: x = 0 \\  \\ \bigg(  \frac{2}{3} \bigg)^{0}  = 1

5 0
3 years ago
Can someone give me the answers to this or how to find the answers to it?
faltersainse [42]

the discriminant formula is b^2-4ac

so plug the values from each equation into the formula and solve, the result is the value of the discriminant

if the number is negative, there are no real roots/x-int

if it is 0 there is one real root/x-intercepts

if it is positive it has 2 real roots/x-int

and to find the actual solutions you have to plug the values into the quadratic formula

6 0
4 years ago
On a​ map, 1 inch equals 20 miles. Two cities are 8 inches apart on the map. What is the actual distance between the​ cities?
8_murik_8 [283]

If 1 inch equals 20miles then 8 inches equals 20 x 8 = 160 miles.

6 0
3 years ago
Read 2 more answers
Evaluate S(3)=10+20log4(3+1)
dimulka [17.4K]
Asssuming you mean

evaluate 10+20log_4(3+1)

remember log_a(a)=1
so
10+20log_4(3+1)=
10+20log_4(4)=
10+20(1)=
10+20=
30
4 0
3 years ago
3. Consider the linear equation 2y - 3x = 5.
nignag [31]

Answer:

Step-by-step explanation:

a.

2y - 3x = 5

2(-2) - 3x = 5

-4 - 3x = 5

-3x = 9

x = -3

(-3,-2) is another solution

b.

(-1,1)

2y - 3x = 5

2(1) - 3(-1) = 5

2 + 3 = 5

5 = 5

true, the point is a solution to the equation because the equation is true after substituting x and y with the point (-1,1)

(4,1)

2y - 3x = 5

2(1) - 3(4) = 5

2 - 12 = 5

-10 = 5

not true, the point is not a solution to the equation because the equation is not true after substituting x and y with the point (4,1)

c. You can use the points from the given (-1,1) and (-3,-2) to form a line. You then shade whichever half solves the solution using points on the graph.

8 0
2 years ago
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