In the problem 56x31, what are the partial products? To acquire the possible partial products we can just multiply the two numbers to produce the possible numbers at hand. <span><span>
1. </span>56 x 31 = 1736</span><span><span>
2. </span>31 x 56 = 1736</span><span> </span>
<span>Same outcome which is explained by the comutative property of multiplication.</span>
Answer:
1/46656 I believe. probability isn't really my strong suit tho.
Step-by-step explanation:
1/6 chance for rolling a one × 1/6 chance of rolling a two and so on.
so you get
1/6 × 1/6 × 1/6 × 1/6 × 1/6 × 1/6 = 1/46656
Answer:
The answer to your question is:
Step-by-step explanation: The third one is a factor
Factor
5x³ − 135
Find the prime factors of 135
135 3
45 3
15 3 Then 135 = 3³ x 5
5 5
1
5x³ - 5(3)³
Factor 5
5[ x³ - (3)³]
5 [ (x - 3)(x² + 3x + 9)]