Ask question

Ask question

All categories

3 years ago

8

PLEASE SHOW FULL SOLUTIONS!! Will Mark Brainliest for the best answer. The radius of a spherical balloon is 3.5 cm. What is the

volume of air in the balloon? Show your answer in terms of pi or round your answer to one decimal place.
THANKS

1 answer:

Vladimir79 [104]3 years ago

7 0

9514 1404 393

Answer:

343π/6 cm³ ≈ 179.6 cm³

Step-by-step explanation:

The formula for the volume of a sphere is one of the volume formulas worth memorizing. It is ...

V = (4/3)πr³

For r = 3.5 cm, the volume is ...

V = (4/3)π(3.5 cm)³ = 343π/6 cm³ ≈ 179.6 cm³

The volume of air in the balloon is about 179.6 cm³.

You might be interested in

Find the next two terms for the following pattern 1, -2, 2, -4, 0

Oxana [17]

After figuring out a common difference in this pattern, we can get further terms in the pattern:
1, -2, 2, -4, 0, -3, -1

5 0

2 years ago

What do you call it when 50 people stand on a wooden dock

Helen [10]

Pier pressure lolllllllllllllllllllllllll

3 0

3 years ago

Read 2 more answers

HELP!! VERY TIME TIME SENSITIVE

guapka [62]

Answer:

B is your correct answer

Step-by-step explanation:

3 0

2 years ago

Help asap my last question GIVING BRAINLIST!!!!

Alex

Answer:

1) $x < 0$

2) $x > 0$

3) $x < 10$

4) $x < -\frac{31}{55}$

5) $x \geq 0$

6) $x \geq -1$

Step-by-step explanation:

1) $-3 > 2x -3$

$2x- 3 < -3$

$2x - 3 + 3 < -3 +3$

$2x < 0$

$\frac{2x}{2} < \frac{0}{2}$

$x < 0$

2) $5 > -x + 5$

$-x + 5 < 5$

$- x + 5 -5 < 5 - 5$

$-x < 0$

$\frac{-x}{-1} < \frac{0}{-1}$

$x > 0$

3) $\frac{x}{5} -2 < 0$

$5 \times (\frac{x}{5} - 2 ) \times 5 < 0$

$x - 10 < 0$

$x -10 + 10 < 0 +10$

$x < 10$

4) $-5x + 11 > 31$

$-5x \cdot 11 < 31$

$-55x < 31$

$\frac{-55x}{-55} > \frac{31}{-55}$

$x < -\frac{31}{55}$

5) $\frac{1}{2}x - 4 \geq -4$

$\frac{1}{2}x -4 +4 \geq -4 +4$

$\frac{1}{2}x \geq 0$

$\frac{\frac{1}{2}x }{\frac{1}{2} } \geq \frac{0}{\frac{1}{2} }$

$x \geq 0$

6) $-4x + 2 \leq 6$

$-4x +2 - 2 \leq 6 -2$

$-4x < 4$

$\frac{-4x}{-4} \leq \frac{4}{-4}$

$x \geq -1$

6 0

3 years ago

Expand each expression

matrenka [14]

Answer:

Option B - $\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Step-by-step explanation:

Given : Expression $\ln(\frac{4y^5}{x^2})$

To find : Expand each expression ?

Solution :

Using logarithmic properties,

$\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B$

and $\ln (AB)=\ln A+\ln B$

Here, A=4y^5 and B=x^2

$\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}$

$\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2$

$\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2$

Using logarithmic property, $\logx^a=a\log x$

$\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Therefore, option B is correct.

3 0

3 years ago

Read 2 more answers