The answer to the question
Answer: $4,365.10
Step-by-step explanation:
Ok, we know that:
The account starts with $2350
There is a simple interest of 3.75% (or 0.035).
Then after one year, the amount in the account will increase by 3.75%, this means that the amount will be:
$2350 + 0.035*$2350 = (1.035)*$2350.
After another year, we have the same increase (but applied to the new amount in the account):
(1.035)*$2350 + 0.035*(1.035)*$2350. = (1.035)^2*$2350
And so on.
You already can see the pattern here, the amount of money in the saving account after N years will be:
M(N) = $2350*(1.035)^N.
Now we can answer:
what is the balance of the account if it earns a simple interest of 3.75% for 18 years?
Just replace N by 18 in that equation:
M(18) = $2350*(1.035)^18 = $4,365.10
Equation = y = mx + b
y = 3/4x + b
Calculation for b.,
-5 = 3/4 * 4 + b
b = -5/3
So, your final answer is y = 3/4x - 5/3
Hope this helps!
If n = $3 then plug it in
$10 + ($6-$3)
$6-$3 = $3
$10 + $3 = $13
4(-9*x)
Multiply the two numbers
-36x
Final answer: -36x
