Answer:
4
Explanation:
<em>The number of progeny expected to display the dominant phenotype for both the A and B genes should be 4.</em>
<u>A test cross usually involves crossing an individual whose zygosity is in doubt with an individual that is recessive for both alleles so as to ascertain the zygosity of the former.</u> Hence, for a test cross involving AaBb:
AaBb x aabb
Progeny:
4 AaBb
4 Aabb
4 aaBb
4 aabb
<em>Therefore, the number of progeny expected to display the dominant phenotype for both the A and B genes is 4.</em>
Answer:
The correct answer is -
Parent 1: RW, Parent 2: RR
Explanation:
In the given punnet square there are four offspring and it is a monohybrid cross between parent 1 and parent 2. The four offspring produced in this cross have RR, RR, RW, and RW alleles. By the genotype of the offsprings, it is clear that there are 50 percent pure or true-bred and 50 percent are heterozygous.
Each parent contribute two alleles and these alleles are independently assort in the zygote to form offspring so there must be R, R, R and W allele present in the parent
Parent 2 → R R
Parent 1 ↓ R RR RR (one allele (R) come from each parent in zygote)
W RW RW (one allele (R and W) come from each parent)
Answer:
C
Explanation:
Parasitism is a relationship between two different organisms where the parasite harms the host.
Answer:
A. The version of the trait that is expressed over other alleles for the same trait.
Explanation:
It is called dominant because if it is present, even in heterozygous situations, it will be expressed.
