here,
2x-6y= -12
2(x-3y)= -12
x-3y = -6...........eq1
x+2y=14............eq2
we can subtract the above two given equations
we get,
___________
so,
y=4
now to find the value of x we have to substitute the value of y in any of the above two equations, I choose eq2
we get,
Answer:
p² -16pq + 36q²
Step-by-step explanation:
Given
(- p + 6q)²
= (- p + 6q)(-
p + 6q)
Each term in the second factor is multiplied by each term in the first factor, that is
- p(-
p + 6q) + 6q(-
p + 6q)
= p² - 8pq - 8pq + 36q² ← collect like terms
= p² - 16pq + 36q²
