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4 years ago

What is the answer to 2/12 as an equivalent fraction

Mathematics

2 answers:

Alex73 [517]4 years ago

8 0

2/12 simplified would be 1/6 so that would be an equivalent fraction

Answers
1/6
4/24
3/36
4/48

Rama09 [41]4 years ago

4 0

Answer:

1/6

20/120

Step-by-step explanation:

You might be interested in

Convert 1 1/3 to decimal

muminat

it will be 1.33= 1 1/3

3 0

3 years ago

Read 2 more answers

Joe collects Pokemon cards. He already has 100 and buys a dozen more each week when he goes to the store. Jessica also collects

Tomtit [17]

Answer:

5 weeks

Step-by-step explanation:

To find the answer to this question we have to write an equation for both situation and put them equal to each other.

Let's write an equation for Joe:

12x + 100

Now, for Jessica

6x + 130

Next, put them equal to each other:

12x + 100 = 6x + 130

Solve:

12x + 100 = 6x + 130

6x + 100 = 130

6x = 30

x = 5

Therefore, it will take 5 weeks for Joe and Jessica to have the same amount of cards.

Check:

12(5) + 100 = 6(5) + 130

60 + 100 = 30 + 130

160 = 160

I hope this helps!!

- Kay :)

5 0

3 years ago

a canoe rental service charges a $20 transportation fee and $30 dollars an hour to rent a canoe. Write and graph an equation rep

True [87]

Use slope intercept form to write the equation y=mx+b m (slope of the line) will be the hourly fee, and b (y-intercept) will be the one-time transportation fee.
y=30x+20

to find the cost of renting a canoe for 6 hours, plug 6 into the equation replacing x
y=(30×6)+20
y=180+20=$200

Sorry, I can't graph the line, but I would number the x-axis of the coordinate plane (graph) by 1s or 2s (for the hours), and the y-axis by 20s (for the cost)

7 0

3 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago

100 4/9 + 61 8/11 + 118 1/2 = ? Please show work

IRISSAK [1]

$100 \frac{4}{9} + 61 \frac{8}{11} + 118 \frac{1}{2} \\ = \frac{400}{9} + \frac{488}{11} + 59$
$\frac{4400 + 4392 + 5841}{99} = \frac{14633}{99}$

hope this helps

3 0

3 years ago