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lbvjy [14]
1 year ago
9

Now can you answer this one.

Mathematics
2 answers:
Mamont248 [21]1 year ago
5 0
1500.50 that’s what I put
Bad White [126]1 year ago
3 0

Answer:

1500.50

Step-by-step explanation:

u need to multiply 212 x 7 and then add together 14 quarters

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Find the probability of the following events , when a dice is thrown once:
Fudgin [204]

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

7 0
3 years ago
Read 2 more answers
Find all the factor pairs for 84 and complete the equations.
VMariaS [17]
1. 84 = 1 x 84

2. 84 = 2 x 42

3. 84 = 3 x 28

4. 84 = 4 x 21

5. 84 = 6 x 14

6. 85 = 7 x 12


Hope this helps!
5 0
3 years ago
-91=13n How would you work out this math problem
Igoryamba

Answer:

n=-7

Step-by-step explanation:

For this you can do the inverse of division which is division. So Divide -91 and 13. Which is -7.

7 0
3 years ago
Read 2 more answers
Which of these students is least likely to qualify for the national spelling bee in June?
mario62 [17]

Answer:

tony

Step-by-step explanation:

his fraction is the greatest meaning that it's also the lowest

8 0
3 years ago
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Use your choice of equal values, substitution, or elimination to solve the
Blizzard [7]

Answer:

For this scenario, I used the elimination method. Organize the equations, so it's easier to subtract from each other. My x-variable will represent the number of hot dogs and my y-variable will represent the number of sodas.

3x+2y=213

x  + y =87

We need to make sure one of the monomials are alike in each equation, so we can eliminate a variable. Distribute 3 to each number/variable in the second equation.

3x+2y=213

3(x+y=87) --> 3x+3y=261

Now we can eliminate x.

  3x+2y=213

-  3x+3y=261

----------------------

        -y=-48  

Divide -1 to both sides to get y=48. So, you sold 48 cans of soda. Now, we can find the number of hot dogs by substituting 48 into the second equation to get x+48=87. Subtract 48 to both sides to result with x=39. So, you sold 39 hot dogs.

7 0
2 years ago
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