The hourly rate is $3 a hour with a $2 initial fee.
Answer:
51 meters
Step-by-step explanation:
Steve is turning half his backyard into a chicken fan. His backyard is a 24 m x 45 m rectangle. He wants to put a chicken wire fence that stretches diagonally from one corner to the opposite corner. How many meters of fencing will Steve need?
We are to find the meters of fencing for the diagonal.
We solve the question using Pythagoras Theorem
= c² = a² + b²
Where
c = Diagonal
a = Width
b =Length
Diagonal² = Width² + Length ²
Hence:
Diagonal ² = 45² + 24²
Diagonal = √45² + 24²
Diagonal = √(2601)
Diagonal = 51 m
Therefore, the meters of fencing for the diagonal that Steve would be needing = 51 meters
Answer:
Take the coordinates of each vertex (corner point) and subtract 2 from the x-coordinate; leave the y-coordinate alone.
Step-by-step explanation:
Example: If one vertex is the point (5, 3), then it moves left 2 units to (3, 3).
If a vertex is at (-3, 1), then it moves 2 units left to (-5, 1).
We have
3 / (x-5) - x/5
We make the GCF and we have
15/[ 5(x-5) ] - x(x-5)/[ 5(x-5)]
= [ 15 - x(x-5) ] [5(x-5)]
= [ 15 - x^2 + 5x] / [ 5 (x-5) ]
= [15 - x^2 + 5x]/[5x - 25]
An answer to your question is (15-x^2+5x)/(5x-25)
