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forsale [732]
3 years ago
10

Pllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllllzzzzzzzzzzzzzzzzzzzzzz

Mathematics
1 answer:
Brrunno [24]3 years ago
4 0

Answer:

i=7.6h, 60.8 inches (B)

Step-by-step explanation:

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15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
Find the midpoint (8, -6) (6,5)​
andrey2020 [161]
I think it’s (7, -0.5)
7 0
2 years ago
Four students were asked to write an expression which has terms that have a greatest common factor of 8c. The expressions provid
wel

Answer:

Wyatt wrote the correct expression

Step-by-step explanation:

Here we are to evaluate which of the students wrote an expression with the highest common factor being 8c

For Tanya; 32c + 16c; 16c( 2 + 1); This is wrong as the highest common factor is 16c

For Wyatt, we have 8c - 48cd; factorizing, we have 8c(1-6cd); This is correct

For Xavier we have 36c-24c; 8 is not a factor of 36, so it won’t work

For Yang 8c + 40; 8(c+ 5); what we are trying to look for is 8c and not 8 so this is wrong also

3 0
3 years ago
Read 2 more answers
Write each of the following expressions without using the absolute value sign. |x−4| if x>4. PLEASE INCLUDE EXPLANATION!!!
kotykmax [81]
The answer is 3.141529

<span>I'm right.</span>
3 0
3 years ago
Can someone help me with this?
timama [110]

Answer:

-9m and 3m

and

3 and - 8

Step-by-step explanation:

In algebra, like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers.

5 0
3 years ago
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