Answer:
Step-by-step explanation:
If the engine torque y (in foot-pounds) of one model of car is given by y=−3.75x^2+23.2x+38.8
The engine speed is at maximum if dy/dx = 0
dy/dx = -2(3.75)x+23.2
dy/dx = -7.5x + 23.2
since dy/dx = 0
0 = -7.5x + 23.2
7.5x = 23.2
x = 23.2/7.5
x = 3.093
Hence the maximum torque is 3.09 rev/min
Answer: Find the area of the parallelogram. Answer is A=54
6 cm
7.5cm
9cm
Step-by-step explanation: get the base and the height and then multiply
Since 93p+84=85
subtract 84 from both sides
93p=1
p=(1/93)