Answer:
Step-by-step explanation:
Group Before After
Mean 80.27 78.27
SD 12.76 12.92
SEM 3.85 3.89
N 11 11
df = 10
standard error of difference = 0.798
The mean of Before minus After equals 2.00
Given a=0.01, |t(0.005, df=10)|=3.17 (check student t table)
So 99% CI is
2±t*s
--> 2±3.17*0.798
--> -0.5 < µd< 4.5
Answer:-0.5 < µd< 4.5
Answer:
y=4
Step-by-step explanation:
There are 20 us tons in 40,000 pounds.
Answer:
(a) 4i times
(b) "i × n" times
Step-by-step explanation:
(a) Given the algorithm segment;
for i := 1 to 4, (Outer loop)
for j := 1 to i (Inner loop)
next j,
next i
The inner loop runs for i times, while the outer loop runs for 4 times.
The total times the inner loop would run when the entire algorithm is run is:
= i × 4
= 4i times
(b) Given the algorithm segment;
for i := 1 to n, (Outer loop)
for j := 1 to i (Inner loop)
next j,
next i
Where n is a set of positive integers.
The inner loop runs for "i" times, while the outer loop runs for "n" times.
The total times the inner loop would run when the entire algorithm is run is:
= i × n
= "i × n" times
Answer:
MmMm
Step-by-step explanation:
5 points thanks eheheheheh report me pls
Also for question 2a answer is 10.25p=h, i think just use the formula y=kx
