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posledela
3 years ago
11

How do I show work ? Plz help me

Mathematics
2 answers:
Nata [24]3 years ago
4 0
Draw the shape and if you do that try imagining cutting it in half <span />
nadya68 [22]3 years ago
3 0
A circle because if you cross-section it its like cutting it in half horizontally. So its like seeing it from the top view and you would see a circle.
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What is the slope of y=5/2x - 4. and what is the y intercept
miskamm [114]

Answer:

Slope is 2/3

y-intercept is 1

Step-by-step explanation:

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2 years ago
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Appropriate Inverse Operation
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Multiplying both sides of the equation by 3 and substituting 4 for p
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Sveta_85 [38]

Answer:4/125

Step-by-step explanation:

5 0
2 years ago
Literal equations 2x-3y=8 solve for y
vichka [17]
2x-3y = 8

Add 3y on both sides

2x = 8 + 3y

Subtract 8 on both sides

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4 0
3 years ago
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Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
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