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BigorU [14]
3 years ago
13

Suppose three out of every five people said they would prefer a television over a computer. If we surveyed 5,000 people, how man

y would prefer a television?
Mathematics
2 answers:
liberstina [14]3 years ago
7 0
3,000 people because 3/5 is 0.6, so all you have to do is multiply 5,000 by 0.6 to get 3,000. Also, 3000/5000 is like 3/5, just with more zeros. Hope I helped!
Darina [25.2K]3 years ago
4 0

Answer:

3,000 is your answer

Step-by-step explanation:

so you set it up: 3/5 = x/5000

5(x)= (3)(5000)

3 X 5,000 = 15000

15000 = 5x

divide each side by 5, 5x and 5 cancel out and (15000 /5 =3,000) that will leave you with an answer of 3,000

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The ability to find a job after graduation is very important to GSU students as it is to the students at most colleges and unive
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Answer: (0.8468, 0.8764)

Step-by-step explanation:

Formula to find the confidence interval for population proportion is given by :-

\hat{p}\pm z^*\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p}  = sample proportion.

z* = Critical value

n= Sample size.

Let p be the true proportion of GSU Juniors who believe that they will, immediately, be employed after graduation.

Given : Sample size = 3597

Number of students  believe that they will find a job immediately after graduation= 3099

Then,  \hat{p}=\dfrac{3099}{3597}\approx0.8616

We know that , Critical value for 99% confidence interval = z*=2.576  (By z-table)

The 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation will be

0.8616\pm(2.576)\sqrt{\dfrac{0.8616(1-0.8616)}{3597}}

0.8616\pm (2.576)\sqrt{0.0000331513594662}

\approx0.8616\pm0.0148\\\\=(0.8616-0.0148,\ 0.8616+0.0148)=(0.8468,\ 0.8764)

Hence, the 99 % confidence interval for the proportion of GSU Juniors who believe that they will, immediately, be employed after graduation. = (0.8468, 0.8764)

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Answer:

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Step-by-step explanation:

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