Will give brainlist
1 answer:
You might be interested in
Answer:
The angular velocity is
Explanation:
From the question we are told that
The mass of each astronauts is
The initial distance between the two astronauts
Generally the radius is mathematically represented as
The initial angular velocity is
The distance between the two astronauts after the rope is pulled is
Generally the radius is mathematically represented as
Generally from the law of angular momentum conservation we have that
Here is the initial moment of inertia of the first astronauts which is equal to
the initial moment of inertia of the second astronauts So
Also is the initial angular velocity of the first astronauts which is equal to
the initial angular velocity of the second astronauts So
Here is the final moment of inertia of the first astronauts which is equal to
the final moment of inertia of the second astronauts So
Also is the final angular velocity of the first astronauts which is equal to
the final angular velocity of the second astronauts So
So
=>
=>
=>
=>
Answer:
a) 6 times farther. b) 6 times longer.
Explanation:
Once released, in the horizontal direction, no other forces act on the ball, so it continues moving at the same initial velocity, which is given by the projection of the velocity vector in the horizontal direction, as follows:
vₓ = v* cos (25º) = 23 m/s * 0.906 = 20.8 m/s
In the vertical direction, the initial velocity is the projection of the velocity vector along the vertical axis, as follows:
vy = v* sin (25º) = 23 m/s * 0.422 = 9.72 m/s
Assuming that the acceleration is constant, and equal to 1/6*g, we can calculate the total time of flight, with the following kinematic equation for the vertical displacement:
If the total displacement in the vertical direction is 0 (which means that the time if the total time of flight), we can solve for t, as follows:
On earth, this time could be calculated in the same way:
As the time is defined by the vertical movement, we can find the horizontal distance travelled on the moon, as follows:
Δx = v₀ₓ * t = 20.8 m/s * 11. 9 s = 248.1 m
On earth, the distance travelled had been as follows:
Δx = v₀ₓ * t = 20.8 m/s * 1.98 s = 41.3 m
⇒ Δx(moon) / Δx(earth) = 248.1 / 41.3 = 6.00
b) As we have just found, the time of flight on the moon and on the earth are as follows:
tmoon = 11. 9 s
tearth = 1.98 s
⇒ t(moon) / t(earth) = 11.9 / 1.98 = 6.0