Explanation:
Camels have wider hoofs, the reduced pressure of their feet makes the camel run faster in the desert. Their eyes are used to blowing sand so it does not affect their speed.
As they have a wider hoofs their foot dont sink in sand so they can easily run or walk.
Answer:
M2 = 0.06404
P2 = 2.273
T2 = 5806.45°R
Explanation:
Given that p1 = 10atm, T1 = 1000R, M1 = 0.2.
Therefore from Steam Table, Po1 = (1.028)*(10) = 10.28 atm,
To1 = (1.008)*(1000) = 1008 ºR
R = 1716 ft-lb/slug-ºR cp= 6006 ft-lb/slug-ºR fuel-air ratio (by mass)
F/A =???? = FA slugf/slugaq = 4.5 x 108ft-lb/slugfx FA slugf/sluga = (4.5 x 108)FA ft-lb/sluga
For the air q = cp(To2– To1)
(Exit flow – inlet flow) – choked flow is assumed For M1= 0.2
Table A.3 of steam table gives P/P* = 2.273,
T/T* = 0.2066,
To/To* = 0.1736 To* = To2= To/0.1736 = 1008/0.1736 = 5806.45 ºR Gives q = cp(To* - To) = (6006 ft-lb/sluga-ºR)*(5806.45 – 1008)ºR = 28819500 ft-lb/slugaSetting equal to equation 1 above gives 28819500 ft-lb/sluga= FA*(4.5 x 108) ft-lb/slugaFA =
F/A = 0.06404 slugf/slugaor less to prevent choked flow at the exit
Producido a partir de un experimento de laboratorio ido mal, las tortugas adolescentes Leonardo, Michelangelo, Donatello y Raphael viven en las alcantarillas bajo Nueva York. Aunque su sensei roedor, Splinter, aconseja no mostrarse sobre el suelo, los hermanos amantes de la justicia y que comen pizza no pueden permanecer ociosos mientras el malvado Shredder y sus secuaces aterrorizan a la ciudad. Con ayuda de la intrépida reportera April O'Neil (Megan Fox) y su camarógrafo (Will Arnett), las Tortugas salieron a salvar a Nueva York.
espero que esto ayude :)
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Answer:
your friend will wait for you for 2.2 minutes.
Explanation:
Given;
Distance of the journey, d = 50 km
your speed, v₁ = 88.5 km/h
your friends speed, v₂ = 94.5 km/h
The time taken before you reached the end of the trip;
![time = \frac{distance }{speed} \\\\t_1 = \frac{d}{v_1} \\\\t_1 = \frac{50}{88.5} \\\\t = 0.565 \ hour](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7Bdistance%20%7D%7Bspeed%7D%20%5C%5C%5C%5Ct_1%20%3D%20%5Cfrac%7Bd%7D%7Bv_1%7D%20%5C%5C%5C%5Ct_1%20%3D%20%5Cfrac%7B50%7D%7B88.5%7D%20%5C%5C%5C%5Ct%20%3D%200.565%20%5C%20hour)
The time taken before your friend reached the end of the trip;
![time = \frac{distance }{speed} \\\\t_2 = \frac{d}{v_2} \\\\t_2 = \frac{50}{94.5} \\\\t = 0.529 \ hour \\\\](https://tex.z-dn.net/?f=time%20%3D%20%5Cfrac%7Bdistance%20%7D%7Bspeed%7D%20%5C%5C%5C%5Ct_2%20%3D%20%5Cfrac%7Bd%7D%7Bv_2%7D%20%5C%5C%5C%5Ct_2%20%3D%20%5Cfrac%7B50%7D%7B94.5%7D%20%5C%5C%5C%5Ct%20%3D%200.529%20%5C%20hour%20%5C%5C%5C%5C)
The difference in time = (0.565 - 0.529) hour
= 0.036 hour
= 0.036 x 60 min
= 2.2 mins
Therefore, your friend will wait for you for 2.2 minutes.