The Biggest star in our universe is the sun. Although the largest in the galaxy is the <span>VY Canis Majoris which is about 3,900 to 5000 light years away from us.</span>
Answer:
Explanation:
From the question we are told that
The initial velocity is 
The time taken is 
The charge to mass ratio is 
Generally the acceleration is mathematically evaluated as

substituting values

The electric field is mathematical represented as

substituting values


Answer:
Required time, t = 0.84 seconds
Explanation:
It is given that,
Initial speed of an object, u = 22 m/s
Final velocity of an object, v = 27 m/s
Acceleration, a = 5.93 m/s²
We have to find the time required for an object to go a speed of 22 m/s to a speed of 27 m/s. It can be solved by using first equation of motion as:

Where
t = time


t = 0.84 seconds
Hence, the time required for an object is 0.84 seconds.
Answer:
<em>0.153 m/s</em>
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Explanation:
The flowrate Q = 0.625 x 10-3 m^3-/s
The diameter of the nozzle d = 5.19 x 10^-3 m
the velocity V = ?
The cross-sectional area of the flow A = 
==> (3.142 x 5.19 x 10^-3)/4 = 4.077 x 10^-3 m^2
From the continuity equation,
Q = AV
V = Q/A = (0.625 x 10-3)/(4.077 x 10^-3) = <em>0.153 m/s</em>
To determine the acceleration of the car, we use equation of motion
Here, v is final velocity of the car, u is the initial velocity of the car, a is the acceleration of the car in time t.
Given,
, u=0 because car accelerate from 0 and t = 3.40 s.
Substituting these values in above equation, we get

In mi/ h.s,
1 m = 0.000621371 mile.
1 s = (1/3600 ) hour = 0.000277778 hour.
Therefore,
