The energy stored in a capacitor is

**E = (1/2) · (capacitance) · (voltage)²**

E = (1/2) · (6 x 10⁻⁶ F) · (12 V)²

E = (3 x 10⁻⁶ F) · (144 V²)

<em>**E = 4.32 x 10⁻⁴ Joule**</em>

(That's 0.000432 of a Joule)

The answer is <em>**B. 5/4**</em>** ** or <em>**1.25**</em>

<span>93.3°C

A temperature in Fahrenheit (°F) can be converted to Celsius (°C), using the formula

[°C] = ([°F] − 32) × 5⁄9. Here we have to convert a temperature of 200°F in to Celsius. Thus Subtract 32 from Fahrenheit and multiply by 5 then divide by 9 .
That is (200°F - 32) × 5/9=168 × 5/9

=840/9

=93.333333333°C

= 93.3°C</span>

To solve the problem it is necessary to apply conservation of the moment and conservation of energy.

By conservation of the moment we know that

Where

M=Heavier mass

V = Velocity of heavier mass

m = lighter mass

v = velocity of lighter mass

That equation in function of the velocity of heavier mass is

Also we have that

On the other hand we have from law of conservation of energy that

Where,

W_f = Work made by friction

KE = Kinetic Force

Applying this equation in heavier object.

Here we can apply the law of conservation of energy for light mass, then

Replacing the value of

Deleting constants,

When the temperature of an object that is giving off light is increased, the particles in the object will move at a faster rate and there will be increased vibration of these molecules. This will makes the object to emit more light and to shine more brightly.