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Vikentia [17]
3 years ago
9

Conclusion on ohm's law experiment ​

Physics
1 answer:
Free_Kalibri [48]3 years ago
6 0

Answer:

Explanation:

In our previous articles, we observed the theoretical formulas of Ohm’s law, its calculations in the lab report, and experiment. Today you’ll learn the verification of theory vs experimental results on a 1 kΩ resistor.

The theoretical results are obtained from the formula of Ohm’s law: V = IR. The experimental verification is provided for a metal film 1 kΩ (±0.05%). We have used a high-quality resistor with negligible tolerance value so as to reduce the tolerance error.

The little problem in our calculations arises due to improper handling of multimeter probes. You can learn the complete method to perform the Ohm’s experiment here and can calculate the current values by using the Ohm’s law calculator.

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Conductors have magnetic fields; insulators do not have magnetic fields. Conductors do not have magnetic fields; insulators do have magnetic fields. ... In a conductor, electric current cannot flow freely; in an insulator, it can flow freely.

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Greg throws a 2.8-kg pumpkin horizontally off the top of the school roof in order to hit Mr. H's car. The car has parked a dista
Igoryamba

Answer:

The horizontal velocity is v = 9.2 m/s

Explanation:

From the question we are told that

     The mass of the pumpkin is  m = 2.8 \ kg

      The distance of the the car from the building's base is  d = 13.4 \ m

       The height of the roof is h = 10.4 \ m

       

The height is mathematically represented as

         h = \frac{1}{2} gt^2

Where g is the acceleration due to gravity which has a value of g =9.8 \ m/s^2

substituting values

          10.4= 0.5 * 9.8 * t

making the time taken the subject of the formula

         t = \frac{10.4}{0.5 * 9.8 }

          t = 1.457 \ s

The speed at which the pumpkin move horizontally can be represented mathematically  as

                         v = \frac{d}{t}

substituting values

                     v =\frac{13.4}{1.457}

                     v = 9.2 m/s

7 0
2 years ago
A 75.0-kg man standing on a bathroom scale in an elevator. Calculate the scale in N, reading if the elevator moves upward at a c
Salsk061 [2.6K]

The scale in N, reading if the elevator moves upward at a constant speed of 1.5 m/s^2 is 862.5 N.

weight of man = 75kg

speed of elevator, a = 1.5 m/ s^{2}

F - w = ma \\

F = w + ma

F = m ( a +g )

F = 75 ( 1.5 + 10 ) \\

F = 75 ( 11.5 )

F = 862.5 N

So, the scale reading in the elevator is greater than his 862.5 N weight. This indicates that the person is being propelled upward by the scale, which it must do in order to do so, with a force larger than his weight. According to what you experience in quickly accelerating or slowly moving elevators, it is obvious that the faster the elevator acceleration, the greater the scale reading.

Speed can be defines as the pace at which the position of an object changes in any direction.  Since speed simply has a direction and no magnitude, it is a scalar quantity.

Learn more about speed here:-

brainly.com/question/19127881

#SPJ4

8 0
2 years ago
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