Answer:
The mass of the bullet is 15 g.
(b) is correct option.
Explanation:
Given that,
Momentum = 2.8 kg m/s
Speed = 187 m/s
We need to calculate the mass of the bullet
Using formula of momentum
Where, P = momentum
v = speed
Put the value into the formula
Hence, The mass of the bullet is 15 g.
Both masses will have the same acceleration. The cart accelerates to the right with a magnitude of 4.9 m/. The correct answer is 4.90 m/
Given that a massless string connects a 1.00 kg mass to a 3.00 kg cart which is resting on a frictionless horizontal surface.
Let M = 1kg and m = 3 kg
Since the horizontal surface is frictionless, the tension in the string will be the same. when the mass is hanged over a frictionless pulley, the tension will also be the same.
When the mass is released, the cart accelerates to the right can be calculated from Newton' second law of motion. That is,
M( g + a) = m(g - a)
1(9.8 + a) = 3( 9.8 - a)
9.8 +a = 29.4 - 3a
collect the like terms
4a = 19.6
a = 19.6/4
a = 4.9 m/
Therefore, the cart accelerates to the right with a magnitude of 4.9 m/. The correct answer is 4.90 m/
Learn more about dynamics here: brainly.com/question/24994188