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Leya [2.2K]
3 years ago
9

Plz help me solve this!!-

Mathematics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

Amy traveled at 4.5 mph, while Jim traveled at 6 mph. Therefore, Jim traveled at a greater average speed.

Step-by-step explanation:

Given that Amy drove her hoverboard 3 miles in 40 minutes, while Jim hopped 2 miles in 20 minutes, to determine who traveled at a greater average speed, the following calculation must be performed:

(3/40) x 60 = Amy's speed

0.075 x 60 = Amy's speed

4.5 = Amy's speed

So Amy traveled 4.5 miles per hour.

(2/20) x 60 = Jim's speed

0.1 x 60 = Jim's velocity

6 = Jim's speed

Instead, Jim traveled 6 miles per hour.

Therefore, Jim was the one who traveled at a greater average speed.

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solong [7]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Jamil finds that he reads 1/5 of his 115-page book in 1/4 hour
Nadya [2.5K]

Answer:

He will read 92 pages in an hour going by the current rate at which he reads

Step-by-step explanation:

The complete question is as follows;

Jamil found that he reads 1/5 of his 115 - page book in 1/4 of an hour. At this rate how many pages does he read in an hour

We proceed as follows;

If he reads 1/5 of 115 in 1/4 hour

1/5 of 115 pages refer to 1/5 * 115 = 23 pages

This means that he reads 23 pages in quarter of an hour

So in an hours the number of pages he will read will be 23 * 4 = 92 pages

6 0
3 years ago
Gene's scores were as follows: 8, 4, 10, 10, 9, 6, 9
Yakvenalex [24]

Answer:

8.4 is the average of all of the scores.

Step-by-step explanation:

Add all of the scores together, and then divide by the number of scores to get the answer. Btw, BNHA is the best lol. Hope this helps! :)

5 0
3 years ago
Activity
Sergio039 [100]

Answer:

A:

Dylan’s weight is d.

Twice Dylan’s weight is 2d.

Three pounds more than twice Dylan’s weight is 2d + 3.

So, the expression for Alan’s weight in terms of Dylan’s weight is 2d + 3.

B:

Dylan’s weight is d.

Three times Dylan’s weight is 3d.

Twelve less than three times Dylan’s weight is 3d − 12.

So, the expression for Bruce’s weight in terms of Dylan’s weight is 3d − 12.

C:

Cecil’s weight is the sum of Alan's weight and Bruce's weight.

Alan’s weight in terms of Dylan's weight is 2d + 3.

Bruce’s weight in terms of Dylan's weight is 3d − 12.

So, the expression for Cecil’s weight in terms of Dylan’s weight is (2d + 3) + (3d − 12).

D:

Cecil's weight is (2d + 3) + (3d − 12).

Find Cecil's weight by substituting Dylan’s weight (d = 45) into the expression above:

(2 × 45 + 3) + (3 × 45 − 12)

=  (90 + 3) + (135 − 12)

=  93 + 123

=  216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

E:

Yes, the expression can be simplified by using the Associative and Commutative Properties of addition and by combining the like terms in the expression.

F:

(2d + 3) + (3d − 12)

First remove the parentheses:

2d + 3 + 3d − 12.

Then group the like terms:

2d + 3d + 3 − 12.

Finally, add and subtract the like terms:

5d − 9.

The expression (2d + 3) + (3d − 12) simplifies to 5d − 9.

G:

Cecil’s weight in terms of Dylan’s weight is 5d – 9.

Find Cecil’s weight by substituting Dylan’s weight (d = 45) into the expression above:

(5 × 45) − 9

= 225 − 9

= 216.

If Dylan weighs 45 pounds, then Cecil weighs 216 pounds.

H:

Yes, the answers are the same. The expression from part D is equivalent to the expression from part G.

I:

Bruce's weight in terms of Dylan’s weight is 3d − 12.

Alan's weight in terms of Dylan’s weight is 2d + 3.

So, the expression (3d − 12) − (2d + 3) represents how much more Bruce weighs than Alan.

J:

The expression is (3d − 12) − (2d + 3).

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

(3 × 45 − 12) − (2 × 45 + 3)

= (135 − 12) − (90 + 3)

= (123) − (93)

= 30.

Bruce weighs 30 pounds more than Alan weighs.

K:

The expression (3d − 12) − (2d + 3) simplifies to d − 15.

L:

The expression is d − 15.

Evaluate the expression by substituting Dylan’s weight (d = 45) into it:

45 − 15 = 30.

Bruce weighs 30 pounds more than Alan. This is the same answer as in part J.

Do not copy, it's the exact answer from edmuentum

5 0
3 years ago
A bag contains 8 red marbles, 2 blue marbles, and 1 green marble. What is the probability of choosing a marble that is not blue?
SVETLANKA909090 [29]

Answer:

it's roughly 82% or for simplicity 9/11

6 0
3 years ago
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