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eduard
3 years ago
11

On a number line, show all values of x for which… |x |< 1

Mathematics
1 answer:
aleksley [76]3 years ago
4 0

Answer:

See attachment

Step-by-step explanation:

We want to show all values of x, for

|x| \: < \:  1

on the number line.

By the definition of absolute value function:

- x \:  <  \: 1 \: or \: x \:  <  \: 1

Divide through the first inequality by -1 and reverse the sign.

x \:   >  \:  - 1 \: or \: x \:  <  \: 1

On the number line, we can represent this as shown in attachment.

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How can you identify the parts of an expression using mathematical terms ?
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<span>An expression containing variables, numbers, and operation symbols is called an algebraic expression. ...Find the terms, coefficient, and degree for this expression: . ...<span>List the terms, coefficients, and degree of each term in the following expression: . ...</span></span>
8 0
2 years ago
A pet store was selling 4 lizards for $47.88. If they ended up selling 6 lizards, how much would they have earned?
fgiga [73]

Answer:

Step-by-step explanation:

Step one- Find out how much it costs for one Lizard In this case, for four lizards it costs $47.88. To find the price for one lizard you divide 47.88 by four

$47.88/4Lizards=$11.97 per lizard.

Step two- Now that we have the price for one lizard, your question asks you how much for 6 lizards. We need to find that cost. To do so you multiply $11.97 by 6 for the lizards.

Your answer is $71.82

Hope This Helped :)

4 0
2 years ago
Read 2 more answers
What is (2x^2+6x-3) added to (2x^3-3x+2)?
Bas_tet [7]
2x² + 6x - 3 + 2x³ - 3x + 2

Combine like terms

2x³ + 2x² + 6x - 3x - 3 + 2

Final answer:
2x³ + 2x² + 3x - 1
8 0
2 years ago
Read 2 more answers
Solve y'' + 10y' + 25y = 0, y(0) = -2, y'(0) = 11 y(t) = Preview
svetlana [45]

Answer:  The required solution is

y=(-2+t)e^{-5t}.

Step-by-step explanation:   We are given to solve the following differential equation :

y^{\prime\prime}+10y^\prime+25y=0,~~~~~~~y(0)=-2,~~y^\prime(0)=11~~~~~~~~~~~~~~~~~~~~~~~~(i)

Let us consider that

y=e^{mt} be an auxiliary solution of equation (i).

Then, we have

y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.

Substituting these values in equation (i), we get

m^2e^{mt}+10me^{mt}+25e^{mt}=0\\\\\Rightarrow (m^2+10y+25)e^{mt}=0\\\\\Rightarrow m^2+10m+25=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow m^2+2\times m\times5+5^2=0\\\\\Rightarrow (m+5)^2=0\\\\\Rightarrow m=-5,-5.

So, the general solution of the given equation is

y(t)=(A+Bt)e^{-5t}.

Differentiating with respect to t, we get

y^\prime(t)=-5e^{-5t}(A+Bt)+Be^{-5t}.

According to the given conditions, we have

y(0)=-2\\\\\Rightarrow A=-2

and

y^\prime(0)=11\\\\\Rightarrow -5(A+B\times0)+B=11\\\\\Rightarrow -5A+B=11\\\\\Rightarrow (-5)\times(-2)+B=11\\\\\Rightarrow 10+B=11\\\\\Rightarrow B=11-10\\\\\Rightarrow B=1.

Thus, the required solution is

y(t)=(-2+1\times t)e^{-5t}\\\\\Rightarrow y(t)=(-2+t)e^{-5t}.

6 0
3 years ago
I need someone to do this for me in STANDERD ALGORITHM ONLY ok here's the question: 2.1x82
statuscvo [17]
172.2 it correct because u have use you brain and u will get the answer u have to try first  and put your mind to it when u do that then u will be able to do anything 
5 0
3 years ago
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