It’s 4, I hope it helps!!
1-2. The best estimate for the population mean would be sample mean of 60 gallons. Since we know that the sample mean is the best point of estimate. Since sample size n=16 is less than 25, we use the t distribution. Assume population from normal distribution.
3. Given a=0.1, the t (0.05, df = n – 1 = 15)=1.75
4. xbar ± t*s/vn = 60 ± 1.75*20/4 = ( 51.25, 68.75)
5. Since the interval include 63, it is reasonable.
Answer: 0.025
Step-by-step explanation: we reject null hypothesis if p<0.05
Answer:
5
Step-by-step explanation:
This problem can be represented in a formula with fractions. To make it more simple, we are converting 5m30s to just pure seconds, which = 154 copies in 330 seconds.
You set up the formula like this: 154/330 = x/60. (it is x/60 because you want to know the x amount of copies per 60 seconds)
Cross multiply, you get 330x = 9240. Divide both sides by 330, you get:
x = 28 copies.
The final answer is 28 copies per minute
